 This is the experimental thing, the composition that you get, you get almost around 99% of the input, that's why it's the most important. This whole operation that you get is the CCL, the problem is CCL, that's the CCL. One more important dimensional case when it enters as a, it forms CCL3. That's why this last one is important. CCL3, I don't know if it's because it's clear. It's the most important form, with silver plus 6 points of ease. This one. This is a little bit more. Let's write down and write. Now when you compare, what's your asset one? CCL, double bond, CCL, double bond, and the point in error is that you have to wait and then react. Yes or no? If you want to break this bond also, then what you get is not involved but involved in resonance. And this is not resonance, it's different. It is there, it is stronger than that of an asset. Correct? So only if the bond is in such a horizontal position, where it will be. Anyway, it's a horizontal position. Yeah, okay, so if there is something, if there is something. I'm telling you. Right? So right now I'm going straight. The reactivity of aryhen, since the aryhen plus m effect ends the carbon halogen bond, which is double bond characteristics, which makes the bond, this carbon halogen bond, stronger than, makes the bond, stronger than that of alkyne halide. Another one, let's write it down. This is the FD item, and then you write it down. Let's say 9 by the other ends. In any event, it's not 7 by the other ends. Hence, the association of carbon halogen bond is difficult. The association of carbon halogen bond is difficult. Next time, one note to write down. When a powerful electron withdrawing loop, when a powerful electron withdrawing loop, that is NO2, CN, COH, CH4, when a powerful electron withdrawing loop, present at ortho or para position, present at ortho or para position, with respect to the halogen atom, then the replacement of halogen atom, then the replacement of halogen atom, like OH- and the replacement of halogen atom, by any nucleophile, like OH- or NH- is possible, is possible. Next point, greater than number of, is possible, when a powerful electron withdrawing loop, present at ortho or para position, more will be its reactivity, more will be its reactivity. Next line, presence of EWG, electron withdrawing loop, presence of EWG, electron withdrawing loop, at metapolition, at metapolition, has NO. This is a few properties of EWG, if you have to memorize. Usually we cannot break out and have them on, but in presence of electron withdrawing loop, that too at ortho or para position is possible. More number of electron withdrawing loop, more will be the reactivity. Now there are few preparation method of EWG we have, and it is not much in reactions here, and it is due to chemical properties that is happening. All these reactions actually are here. The first method is by direct halogenation, right now. The first method of preparation is by direct halogenation. Provenation of benzene ring, Provenation and Provenation of benzene ring. So reactions you see, benzene ring we have, and when it is allowed to react with iotase, Provenation, Provenation of CO2. Direct iodation is not possible, because we will see that. Now when we use this CO2, we can use either reagents like, you know, catties like anhydrous, A-L-C-L3, or we can use FD-C-L3 for high amount of catties. Anhydrous A-L-C-L3 or anhydrous FD-C-L3, all these reagents we can use. And the product we have to reward, we will get photoben-G plus H-C. This is also true when you allow this to react with bromine B-R-G. Ok, correct? Provenation and Provenation is possible. What is the reagent here, catalyst, A-L-B-R-G? Or anhydrous FD-B-R-G? The product A-L plus H-B-L3. But like this we cannot use iotase over here. Why anhydrous? First you copy down this and write down one more here. If you give an excess of B-R-G, and they say under the same partition, when it keeps reacting with the same process, it will stop. It depends. Excess we have to also use, then we will get 2, 4, 6 tribrals more B-G like that. But this is again, this is the thing you have to see in the lab. You may not see it. But possible, like wherever the, but maybe it is possible that only we can ask over here. Because unit of minus i characteristics will be there. That will help. On the metaphor? With respect to this, it is your kind of coordinate. That's why it is a bit difficult. See it is a metaphor with respect to this. So product will end for you. But when you have it, one more thing to write down. Since the reaction is reversible in nature. Since the reaction is reversible in nature, it has more tendency to go in backward direction. For example, you have C6H6 plus I2. This reaction is reversible. C6H5I plus H5. And like I said, it has more tendency to go in backward direction. That's why this reaction is not possible. For ionization what we do? For ionization we use an obsessive agent. Like iodic acid or nitric acid. We use an oxidizing agent like iodic acid or nitric acid. So when this HI reacts with HI O3, that is iodic acid. Plus H2O. When this HIO reacts with HNO3, nitric acid. It gets I2 plus NO2 plus H2O. Now since I2 we are able to react with the ionization. Or we can also write directly this reaction as this. Vendin ring plus I2. And this reaction takes place in presence of an oxidizing agent. Which is H2O. The product here will be I plus HI. And the product here which is here. Here if we add into the reversible reaction. If we add pyridine to react with HI. See, first of all when you ask me to add this. Then maybe theoretically when you look at the reaction it's possible. Like you can say. But actually what happens, what condition you are providing in the lab. That we cannot predict like this. It's not theory. It's not like ok we can see this HNO3 in this. This is actually done in the lab that's why it's given in the lab. So like this you cannot predict. If you add this then what happens. Maybe whatever you are saying is possible that may also not. But you do not know exactly what is the reaction condition you should use to get those products. And in the given set of reactions how the reaction will behave. So that is why we cannot generalize. It depends on the solvent that we are using. It depends even on the temperature that we are using for that reaction. Ok. So that is why it's not the good approach to what happens if we add this. For that we have to do that particular experiment and then we have to observe. Ok. So this is the method. Another method is what we can also prepare this by Dysonium salt. Ok. Next method you write down. One is by direct halogenation. Where we cannot form this hydrodehydrator. Other one is by Dysonium salt. We should have Dysonium salt. We can see Amain's chapter. Write down Dysonium salt which is what from Dysonium salt you write down. And this is the Dysonium salt. We have N2 here and N2 plus and generally we take CmA. N11 and Cm. This is Dysonium benzene Dysonium salt. Ok. If you have to form the correlated CuCl with LCl. Or we can do direct reaction. All these are direct reaction. We will get this reaction directly in the example. So you have to memorize this. Reaction of magnesium salt. Roaming.