 Hello and welcome to the session and this is the following problem today. In the following case state whether the function is 1, 1 onto or bijective. Just if I answer we have function f such that from r to r defined by fx is equal to 3 minus 4x. Now let us write the solution. Given to us is function f such that from r to r defined by fx is equal to 3 minus 4x. Now let us check for 1, 1. Let x, y be two arbitrary elements of r. Then fx is equal to f of y which implies 3 minus 4x is equal to 3 minus 4y which implies x is equal to y minus 3 divided by 4 which is equal to 3 minus y divided by 4. Clearly f is 1, 1. Now let us check for on 2. Let y be an arbitrary element. Then fx is equal to y which implies 3 minus 4x is equal to y which implies x is equal to y minus 3 divided by 4 which is equal to 3 minus y divided by 4. Clearly for all y belongs to r, x is equal to 3 minus y by 4 which belongs to r. Thus for all y belongs to r in code domain there exists x belongs to r in domain given by x is equal to 3 minus y by 4 such that fx is equal to f of 3 minus y by 4 which is equal to 3 minus 4 into 3 minus y by 4 which is equal to y. Thus every element in the code domain has its pre-imagined x thus f is on 2. Now since f is 1, 1 and we have proved that f is also on 2 therefore f function from r to r is a y-jective function. I hope you understood this problem by and have a nice day.