 Hello and welcome to the session. In this session we discussed the phonic question which says evaluate integral sex square x upon 3 plus tan x dx. Let's proceed with the solution now. We take let i be equal to integral sex square x upon 3 plus tan x dx. Here we take let 3 plus tan x be equal to t. Now differentiating both sides we get sex square x dx is equal to dt. So now we get i is equal to integral of, now in place of sex square x dx we put dt upon 3 plus tan x is equal to t. So we get i is equal to integral dt upon t. This means i is equal to log modulus t plus c since integral of dt upon t is equal to log of modulus t and the c is the constant of integration. Now we substitute the value for t as 3 plus tan x. So we get i is equal to log of modulus 3 plus tan x plus c and here the c is the constant of integration. So integral sex square x upon 3 plus tan x dx is equal to log modulus 3 plus tan x plus c. So this is our final answer. This completes the session. Hope you have understood the solution of this question.