 Hi and how are you all today? My name is Priyanka. The question to be discussed is diagonal AC and VD of a trapezius of A,B,C,D with AB parallel to DC. Intercept each other at O. Through that area of A,O,D is equal to area of B,O,C. Now this is the figure which we need to refer. Here we are given that A,B is parallel to DC, right? And also A,B,C,D is a trapezius. Through that area of triangle A,O,D is equal to area of triangle B,O,C. These two triangles we are talking about. Let us start with our proof. We can see that triangle A,B,B and triangle AC,B are on the same base that is AB between the same parallel lines that is AB is parallel to DC, right? So we can say that therefore area of these two triangles will be equal to each other because triangles between the same base and between the same parallel line are equal in area. Now notice that these two triangles are having the area of triangle A,O,B as common. So on subtracting area of triangle A,O,B from both sides we get. Now from the area of triangle AB,B if we subtract this area we are left with this area, right? So we can say that therefore area of A,O,D will be equal to from the area AC,B if we subtract this area we are left with this region. So it is equal to area of B,O,C. So I hope you enjoyed. Have a good day and bye for now.