 Hello and welcome to the session I am Deepika here. Let's discuss the question. A tree is broken at a height of 5 meter from the ground and its top touches the ground at a distance of 12 meter from the base of the tree. Find the original height of the tree. Now we know that Pythagoras property says in a right angle triangle the sphere on the hypotenuse is equal to sum of these squares on the legs. So this is a key idea behind our question. We will take the help of this key idea to solve the above question. So let's start the solution. Now here bd is the height of the tree and tree is broken at a height of 5 meter from the ground. Therefore ab is 5 meter and its top touches the ground at a distance of 12 meter from the base of the tree. Therefore bc is equal to 12 meter. Now ab is equal to ac. So we have a right triangle abc where ab is 5 meter and bc is equal to 12 meter. We have to find the original height of the tree. For this we will first find out ac. So in triangle abc right angle let be we have ab is equal to 5 meter and bc is equal to 12 meter. So by Pythagoras property is equal to ab square plus bc square or ac square is equal to ab square is 5 square plus bc square that is 12 square or ac square is equal to 25 plus 144 or ac square is equal to 169. We can write this as ac square is equal to 13 square. This implies ac is equal to 13. Now the original height of the tree is bd is equal to ab plus ad but ad is equal to ac. So this implies bd is equal to ab which is 5 meter plus ac which is 13 meter and this is equal to 18 meter. Hence the answer for the above question is that the original height of the tree is 18 meter. I hope the solution is clear to you. Pie and take care.