 Hello and welcome to the session. In this session we are going to discuss the following question which says that show that the vectors i is equal to minus 4i cap plus 6j cap plus 10k cap, b is equal to 2i cap plus 4j cap plus 6k cap and c is equal to 14i cap plus 0j cap minus 2k cap are coplanar. We know that 3 vectors a, b, c are coplanar if and only if their scalar triple product is 0 that is scalar triple product of a, b, c is 0. So with this key idea we shall proceed with the solution. Here vector a is given by minus 4i cap plus 6j cap plus 10k cap, vector b is given by 2i cap plus 4j cap plus 6k cap and vector c is given by 14i cap plus 0j cap minus 2k cap and from the key idea we know that 3 vectors a, b, c are coplanar if and only if their scalar triple product is 0. Now scalar triple product of vector a, b, c is given by the determinant of vector a, b and c which is equal to minus 4 into 4 into minus 2 that is minus 8 minus of 0 into 6 that is minus 4 minus of 14 into 6 that is 84 plus 10 into 2 into 0 that is 0 minus of 14 into 4 that is 56 which is equal to minus 4 into minus 8 minus 6 into minus of 28 plus 10 into minus of 56 which is equal to 32 plus 528 minus 560 that is 560 minus 560 which is equal to 0. Therefore, scalar triple product of vector a, b, c is equal to 0 hence the given vectors are coplanar. Complete our session. Hope you will enjoy this session.