 Hi and welcome to the session. Let's work out the following question. The question says solve the following system of linear equations. First is a minus b into x plus a plus b into y is equal to a squared minus 2ab minus b squared and a plus b into x plus y is equal to a squared plus b squared. Let us start with the solution to this question. Now the first equation that we have is a minus b into x plus a plus b into y is equal to a squared minus 2ab minus b squared. We call this equation 1. And the second equation can be rewritten as a plus b into x plus a plus b into y is equal to a squared plus b squared and this we call equation 2. Now we subtract these two equations. So we get a minus b into x minus a plus b into x. This gets cancelled. This is a squared minus a squared is 0. Here we will have minus 2ab minus 2b squared. This implies a minus b minus a minus b into x is equal to minus 2ab minus 2b squared. This implies now plus a gets cancelled with minus a we have minus 2b x is equal to minus 2b into a plus b. Dividing both the sides by minus 2b we get x is equal to a plus b. Now putting the value of x in equation 1 we get a minus b into a plus b plus a plus b into y is equal to a squared minus 2ab minus b squared. This implies now a minus b into a plus b is a squared minus b squared plus this is a plus b into y is equal to a squared minus 2ab minus b squared. This implies a plus b into y is equal to a squared minus 2ab minus b squared minus a squared plus b squared. Now a square gets cancelled with minus a square plus b square with minus b square and we have minus 2ab on the right hand side. This implies that y is equal to minus 2ab upon a plus b. So our answer to this question is that x is equal to a plus b and y is equal to minus 2ab upon a plus b. So I hope that you understood the solution and enjoyed the session. Have a good day.