 Hi and how are you all today? My name is Priyanka and let us discuss this question. It says, a fair die is tossed twice. If the number of bearing on the top is less than 3, it is a success. Find the probability distribution of success. Right? So let us proceed with our solution. We know that when a die is tossed, there is a possibility of bearing one, two, three, four, five or six. Right? Now we are given that it will be a success if the number on the die is less than three. That is the numbers which are less than three over here are one and two. So that means there are two numbers in all that will appear on the top of the die to have a success. So possibility, sorry probability of success is two out of the total number that will appear as six. So that is equal to one by three. Right? So probability that a success will not occur will be equal to if other four numbers appear on the top of the die out of six. So it is equal to two by three. Right? Now here we need to find out the probability distribution of successes. So firstly, if both times no success, so it will be two by three. That is probability of occurring this event will be equal to two by three into two by three because both the times we are not getting a success. So it is equal to four by nine. Secondly, we have one success and one no success. So here it may happen that for the first time success does not occurs and the second time it occurs or first time success occurs but the other time it does not. So we have two by nine plus two by nine which is further equal to again four by nine and lastly the possibility that both time success happens. So it is equal to one by three into one by three. That is one by nine, isn't it? So therefore probability distribution will be like this. No success, one success and both here we have to write down the probability. So here we have the answers as four by nine, four by nine and then one by nine. Right? So this is the required answer to the given question. Hope you understood it well and enjoyed it too. Have a nice day.