 Hi and how are you all today? I am Priyanka. The question says how many 6 digit numbers can be formed from the digits 0, 1, 3, 5, 7 and 9 which are divisible by 10, no digit is repeated. Now let us start with our solution. The given numbers are 0, 1, 3, 5, 7 and 9. Numbers divisible by 10 always have 0 at its units place, isn't it? So we will affix, fix at the units. For the rest 5 places, permutation of remaining 5 numbers can be used, right? So by using term 1 of permutation, there will be as many such numbers as permutation of 5 different numbers taken 5 at a time without repetition. So the required number of permutation is equal to 5P5 that is 5 factorial divided by 5 minus 5 factorial that is 5, 4, 3, 2, 1 getting multiplied by each other divided by 0 factorial that is 120. So 120 is our required answer. I hope you enjoyed. Take care. Remember term 1 of permutation.