 Hello friends welcome to the session I am Alka. I am going to help you find dy by dx in the following. Our equation is y equal to 10 inverse 3x minus x cube upon 1 minus 3x square and minus 1 upon root 3 is less than x is less than 1 upon root 3. So let us start with the solution y equal to 10 inverse 3x minus x cube upon 1 minus 3x square. Now let us assume that x equal to 10 theta this implies theta equal to 10 inverse x. Let this be our first equation. Now this implies y equal to 10 inverse 3 into 10 theta minus 10 cube theta upon 1 minus 3 10 square theta. So since we all know that 10 3 theta is equal to 3 10 theta minus 10 cube theta upon 1 minus 3 10 square theta. Therefore y equal to 10 inverse into 10 3 theta. This implies y equal to 3 theta. This implies y equal to 3 into 10 inverse x by using first. Now differentiate both sides with respect to x we get dy by dx equal to 3 into dy by dx of 10 inverse x. This implies dy by dx equal to 3 upon 1 plus x square. Therefore dy by dx equal to 3 upon 1 plus x square. Hope you understood the solution. I will enjoy the session. Goodbye and take care.