 So now let's take a look at capacitors and circuits where you actually have to solve the full circuit. And this is a strategy that I like to teach my students to help them keep their information organized as they solve the circuit. So let's start with just a two-capacitor circuit. And so we're going to have the first capacitor, the second capacitor, and the equivalent capacitance, as well as the voltages and the charges on each capacitor and the equivalent amount. Each one of the rows are defined by our capacitance equation, which can be rearranged to solve for the voltage or to solve for the charge on each capacitor. Depending on whether my capacitors are in parallel or series, we'd have some column equations. If it's in parallel, it's this set of equations. If it's in series, it's this set of equations. And these are the ones that I derived in my earlier videos. So I'm not going to derive them again. Now let's go ahead and do an example where we're working with parallel. And I'm going to start with some numbers that we've already kind of worked with, with a two-farad capacitor, a three-farad capacitor. And let's connect those in parallel to a 12-volt battery. Well, the trick here with working with this kind of a table is realizing whenever I have a column or row where there's only one blank, I can solve for that blank. In this case, when I look at my first column here, I can find the equivalent capacitance. And in parallel, that's just adding the two. So that will give me my five farads. When I go to the rows then, I notice that on this bottom row, I actually have two values with only one unknown. And so I could solve for the charge by taking my values here and multiplying them. So I would have my five farads times 12 volts, which is going to give me 60 coulombs. Now you might stop at this point and say, but I don't have any rows or columns left with only one unknown. But in the table, there's always going to be one column. And in parallel, it's the voltage column where all the values are equal. And that means once I know my 12 here, I actually know it for each one of these values has to have the same amount. And that means I can now come back in and find my charge 1 and my charge 2 by multiplying the capacitance and the voltage. As an extra check, you'll notice that if I actually go in and add up my two charges, I come up with the same value. And that's my last check because charge 1 plus charge 2 should equal my 60 coulomb charge equivalent. And that's if it's going to be a parallel circuit. So now let's come back here and actually take a look at a series circuit. So I'm going to blank my table out. And I'm going to jump here to my series equations and think about what do I need to do? Again, I start here and I've got my capacitances. So I need to find my equivalent capacitances. Now, I've already worked with this particular one in one of my earlier videos, so I know that that's 1.2 Farads. So now I can come over here and find my charge. And if I take that value, I find that the 1.2 Farads times the 12 volts gives me 14.4 coulombs. Again, one of my columns will be the special column. And for a series circuit, that's the charges. So that means I've got 14.4 here and 14.4 here. To come back and find my voltages then, I would need to fill in the charge divided by the capacitance. So 14.4 divided by 2 gives me the 7.2. And if I do the same thing on the second row, 14.4 divided by 3 gives me 4.8. And as a check, you should make sure that the 7.2 and the 4.8 actually do add up to give me my 12 volts. So if you organize your information, it's easier to see what's associated with each capacitor and what equations do I use for a row versus what equations do I use for a column. And as long as you're given three pieces of information that relate to each one of these rows, we'll have enough information to be able to solve the entire circuit.