 Hello and welcome to the session. I am Deepika here. Let's discuss the question which says Choose the correct answer in the following integral of under root of 1 plus x square dx is equal to a x upon 2 into Under root of 1 plus x square plus 1 by 2 log mod of x plus under root of 1 plus x square plus c b 2.3 into 1 plus x square raised to power 3 by 2 plus c into 1 plus x square raised to power 3 by 2 plus c and d x square upon 2 into under root of 1 plus x square plus 1 over 2 x square log of mod x plus under root of 1 plus x square plus c Now we have a special type of standard integral that is integral of under root of 1 plus a square d x is equal to 1 over under root of x square plus a square plus a square upon 2 log of mod plus a square plus c So this is the idea to solve the above question. So let's start the solution integral of under root of 1 plus x square the idea we have integral of under root of x square plus a square is equal to 1 over 2 plus a square plus a square upon 2 log of the root of x square plus a square upon plus x square d x is equal to 1 over 2 1 square log of mod x plus under root of x square plus 1 square being equal to the root of 1 plus x square upon plus x square Now after me I hope the solution is clear to you. Bye and take care.