 Hi, and welcome to the session. My name is Rashi and I am going to help you with the following question. Question is, solve the following pair of linear equations by the substitution method. First equation is, x minus t is equal to 3 and the second equation is, x upon 3 plus t upon 2 is equal to 6. Let us start with the solution now. First of all, we will rewrite the equations given in the question and name them as 1 and 2. From equation 1, we get s is equal to 3 plus t. Let us name this as 3. Now, we will substitute the value of s in the equation number 2. Now, substituting the value of s in 3 in equation number 2, we get 3 plus t upon 3 plus t upon 2 is equal to 6. Now, this implies, we take the calcium equal to 6 and 2 multiplied by 3 plus t plus 3t is equal to 6. It is equal to 6 plus 2t plus 3t upon 6 equal to 6, which further implies 6 plus 5t is equal to 36 or 5t is equal to 36 minus 6, 5t is equal to 30 or is equal to 30 upon 5 equal to 6. So, t comes out to be equal to 6. Now, we will substitute the value of t in the equation 3. Substituting the value of t in equation 3, we get s is equal to 3 plus t, which is equal to 3 plus 6 or this implies s is equal to 9. So, our required solution is t is equal to 6 and s is equal to 9. Substituting t is equal to 6 and s is equal to 9, we can verify that both equations 1 and 2 are satisfied. So, this completes the session. Hope you understood the session well. Goodbye and take care.