 Hello and welcome to the session. In this session we discuss the following question which says 3 coins are tossed 100 times and we get 3 heads 30 times, 2 heads 20 times, 1 head 20 times and 0 head 30 times. When 3 coins are tossed at random what is the probability of getting 3 heads, 2 heads, 1 head and a 0 head. Before we move on to the solution let's recall the formula to calculate the probability of an event e given by P e and this is equal to the number of trials in which e has happened upon the total number of trials. This is the key idea to be used for this question. Now we proceed with the solution. Now here since we have the 3 coins are tossed 100 times so we have the total number of trials is equal to 100. Next the number of times 3 heads appear is given as 30 times so this is equal to 30 then the number of times heads appear is given as 20 times so this is equal to 20 then the number of times 1 head appear is given as 20 times so this is equal to 20 then the number of times 0 head appear is given as 30 times so this is written as equal to 30. Now when 3 coins are tossed at random we consider even to be an event of getting 3 heads e2 be an event of getting 2 heads e3 be an event of getting 1 head and e4 be an event of getting 0 head. First we shall find the probability of getting 3 heads plus as we have taken even to be an event of getting 3 heads so we will find the probability of the event even this is equal to the number of times 3 heads appear that is 30 upon the total number of trials which is 100 so 30 upon 100 is equal to 0.3 next we find the probability of getting 2 heads now e2 is the event of getting 2 heads so probability of e2 is equal to the number of times 2 heads appear which is 20 upon the total number of trials that is 100 so 20 upon 100 is equal to 0.2 next we find the probability of getting just 1 head now since we have taken e3 to be an event of getting 1 head so probability of e3 is equal to the number of times 1 head appears that is 20 upon the total number of trials which is 100 so this is equal to 0.2 next we shall find the probability of getting 0 head now we have taken e4 to be the event of getting 0 head so probability of e4 is equal to the number of times 0 head appear that is 30 upon the total number of trials which is 100 and this is equal to 0.3 so final answer is probability of getting 3 heads that is probability of even is equal to 0.3 then probability of getting 2 heads is equal to probability of e2 that is equal to 0.2 then probability of getting 1 head is equal to probability of e3 that is equal to 0.2 and the probability of getting 0 head is equal to probability of e4 and this is equal to 0.3 so this is our final answer this completes the session hope you have understood the solution for this question