 Hi and welcome to the session. I am Neha and today I am going to help you with the following question. The question says there is a pentagonal shaped park as shown in the figure. For finding its area, Jyoti and Kavita divided it into two different ways. Find the area of this park using both ways. Can you suggest some other way of finding its area? Let's start its solution. First of all let us mark the points A, B, C, D, E. So A, B, C, D, E is a park in a pentagonal shape. Now let us find out the area of the park in Jyoti's method. Let us name this point as X. Now Jyoti has divided the park by drawing a line AX and dividing the park into two parts that is a trapezium A, B, C, X and another trapezium A, E, D, X. Now both the trapeziums are congruent so that means the area of both the trapeziums will be equal. And to find the area of the park we will find the area of both the trapeziums and we will add them. So let us write area of park is equal to area of trapezium A, B, C, X plus area of trapezium A, E, D, X. For trapezium A, B, C, X, B, C is parallel to AX and B, C is equal to 15 meters, X is equal to 30 meters, X is a perpendicular distance between these two parallel lines. So the height of this trapezium will be CX. So let us write height is equal to CX and now we need to 15 meters equal to XD that means CX and XD are half of CD. So that means CX is equal to half of CD that is half of 15 meters so 15 upon 2 meters. That area is equal to 1 by 2 into where height is the perpendicular distance between these two lines. Therefore area of trapezium A, B, C, X is equal to 1 by 2 into sum of parallel sides that is BC. So this will be equal to BC is 15 meters per meters. So it will be 1 by 2 into 15 meters and CX is equal to 15 by 2 so into 15 by 2 meters. So area of trapezium A, B, C, X and that is equal to 168.75 meters. Therefore we can say that area of park is equal that is 168.75 also 168.75 meters square. The area of the park is 337.5 meters so for triangle to base into so let us find out the lengths of BE and AY to compute the area of the triangle ABE. Now here BE is equal to CD which is so that ED is equal to 15 minus 15 meters that is I is equal to 15 meters. So let us find out the area that will be equal to 1 by 2 into base that is 15 into AY which is also equal to 15 meters. So in this we get 3 of the square BE is equal to 15 meters into 15 new area of triangle ABE that is finding the area of the then we can find its area by dividing it into 3 triangle BDE. Therefore into 10 into 15 37.5 meters square. With this we finish this session. Hope you must have understood the question. Nice day.