 Hello and welcome to the session. In this session we discuss the following question which says, write the value of the determinant with elements 2, 3 and 4 in the first row, 5, 6 and 8 in the second row, 6x, 9x, 12x in the third row. Let's recall one property of the determinants according to which we have that if any 2 rows or columns of a determinant are identical then its value is 0. This is the key idea that we use for this question. Let's proceed with the solution now. We take let delta be equal to the given determinant with the elements 2, 3 and 4 in the first row, 5, 6 and 8 in the second row, 6x, 9x, 12x in the third row. Now from the third row we can take 3x common, so this delta would be equal to 3x determinant with elements 2, 3 and 4 in the first row, 5, 6, 8 in the second row and 2, 3, 4 in the third row. Now in this determinant as you can see that the first and the third row are identical then the value of this determinant would be 0. Therefore we have delta is equal to 3x into 0 which means that delta is equal to 0. And the reason for this is since the 2 rows of the determinant are identical. So therefore the value for the given determinant is 0. Thus the determinant with elements 2, 3, 4 in the first row, 5, 6, 8 in the second row and 6x, 9x, 12x in the third row is equal to 0. So this is our final answer. This is the complete C session. Hope you have understood the solution of this question.