 Hello and welcome to the session. Let's work out the following question. It says, prove the following identity where the angles involved are acute angles for which the expression is different. So let's now move on to the solution. We'll prove that both of these expressions are equal to tan square A. So let's start with this. This is 1 plus tan square A upon 1 plus cot square A. Now we know that 1 plus tan square A is secant square A and 1 plus cot square A is cosecant square A. Now secant square A can be written as 1 upon cos square A, cosecant square A can be written as 1 upon sine square A. This is equal to sine square A upon cos square A which is equal to tan square A. So this expression is equal to tan square A. Now we'll prove that this expression is equal to tan square A. 1 minus tan A upon 1 minus cot A whole square is equal to 1 minus tan A can be written as sine A upon cos A upon 1 minus cot A which is cos A upon sine A whole square. Now taking as here we have cos A minus sine A upon cos A whole square upon sine A minus cos A upon sine A whole square is further equal to cos A minus sine A whole square upon cos square A that is cot A minus sine A upon cos A whole square into sine A upon sine A minus cos A whole square cos A minus sine A whole square upon cos square A into sine square A into taking minus common and since we have square so minus 1 square will be 1 only so this becomes cos A minus sine A whole square. Now cos A minus sine A whole square gets cancelled with cos A minus sine A whole square we are left with sine square A upon cos square A which is equal to tan square A so we have proved that both of the expressions are equal to tan square A hence the result is proved. So this completes the question and the session. My pronoun take care have a good day.