 Are you able to see my presentation? Yeah. Yes, so today we're going to talk about straight lines. We still need to plan what we're going to discuss the following week after this. Because, yeah, all my, my schedule has changed because UNICEF didn't publish all the previous recordings. And because you can watch, I can't say go watch this recording because it's there. So I need to just make sure that I assist you with areas that you are unsure of that you're still struggling with. So by the end of the session today, think of an area that we can discuss the following week so that then I can prepare for that as well. Okay, so today we're talking about straight lines. Before we do that, do you have any questions for me? Or we can also even discuss the plans for next week here. Hi. I would like you to discuss, ma'am, finding X, solving X, finding X, looking for X, X, I need X ma'am. We need to find X. Okay, so today we're also going to find X anyway because I think if X is giving you a problem, hey, we need to find that X. Okay, I will find also some of the exercises from solving X from the previous sessions. And then we can see how we can help you with that. Okay, we'll do that. Thank you ma'am. Are you good? So we can just work with today's session and then proceed from there. Okay, so since we're going to talk about straight lines, straight lines in terms of math or basic numeracy, we always going to refer to them as also linear equation. So you see that we will draw a straight line and that straight line is represented by an equation. And we're going to learn about that. So by the end of the session today, you should learn how to draw a straight line on a set of X-axis. If you look at them, you are not going to be asked to draw a straight line, but you can be asked to identify which straight line corresponds with the information that they have given you. So you should be able to know how that straight line was drawn. We need to determine the slope of a straight line as well as the equation of that straight line. Then we talk about the slope and the straight line. So a straight line is just the line that you draw. Anyone knows what the straight line is. I don't have to explain what the straight line is. So you just need two points and those two points have coordinates within them. What I'm referring to is an axis or a set of X-axis, which we call a Cartesian plane, which is made up of this arrow that goes up and the arrow that goes horizontal. So these are called Y-axis and X-axis. You will see that at the bottom here we do have an X. So the line that is horizontal, we call it the X-axis. The line that is vertical, we call it the Y-axis. If we have only two points and the two points have coordinates that correspond with this Y-axis and the X-axis, we are able to plot that point and when we have the two points, we can connect the two points. For example, if we need to find the slope of a line, we are required to get two points. So let's say we are given these two points. Here it says draw the straight line or the straight line graph that passes through these two points. We are told that the points, these are two points. This is one point, this is one point. We are told that one point has the X coordinate and the Y coordinate because it has to correspond with the X-axis and the Y-axis. So the first point, which is X-one point and corresponds to the Y-one point because this is our point one. It has this coordinate one and four. So we go to the X-axis, we go and state, there is our one. We look for our Y-axis, where it's four, where they both meet. For some reason, my dots are not behind that. There we go. So there is one and there is four. They need to cross-point. And that point that we draw there, it's called point one. It has coordinate of X coordinate one and Y coordinate of four. The second point is that it has X coordinate and our Y coordinate. So this we're going to call it point two and we will represent the X and the Y with the subscript two. So this is our point two. So our point two has on the X-axis four and on the Y-axis two. So where they both meet, that is where our point is at. That is how you define your point. Now, these two points, they tell us something about the type of the line that we have. So when we join this point and that point, we just take a ruler and draw the line to join these two points. And they are the two points they created the line. Now, when you look at this line, you need to be able to tell us whether this line is declining or does it go downwards? Or is it negative or is it positive? So it tells you so many things. So what does it mean? It means when the value of X increases, when our values of X are going up, the values of Y are going down. And therefore it means this slope of this line is what we call a descending slope or what we call a downhill slope. Or we can also call it a negative slope. So let's assume that we have another Cartesian plane here and we have two points, point there and a point here. If I draw a line that joins them, this point for our X-axis, when they are increasing in terms of the X value, because you can see there is our X value and there is our X value in terms of our Y value, because that is our Y value, so our Y-axis. When my X1 is low, my Y1 is also low at that point. When my X2 is high at that point, my Y is also high at that point. So therefore it means when the value of X is increasing, the value of Y is also increasing. And this we call it an ascending slope. And we can also call it a positive slope. Or we can call it an upward slope. And that is how you can define the type of slopes you have. I just want to see if I can actually resist. So let's assume that there is another method where you have the Cartesian plane with your X value there and your Y value there. And there is the line. Looking at this line, you can see that this line is constant, right? This line is constant. When the value of X is at this point, the value of Y, if this was true, the value of Y will just be 2. When the value of X increases from 1 to 2, the value of Y will stay the same. Even when it goes to the negative side, when the value of X is negative 1 this side, the value of Y stays the same as positive 2. So if your slope looks like this for the straight line, we say there is no change in the values of Y. As the values of X increases, there is no change. It's constant. The value of Y is constant and therefore we call this A. It's not a negative, it's not a positive, it's not a downy, it's just a constant slope as well. So we can also have a scenario where it is Y and X exists and you have a constant X value. So when the values of Y increases or decreases, the values of X stays constant because it will be constant at that value there. So you just need to know and remember the types of slopes that you can have. And the slope will be equals to 0, whereas for the others, for this first one, the slope will be negative. When you calculate the slope, you will see later on we will be calculating the slope. When you calculate the slope and you get a negative value, you must know that that is a descending slope, a negative slope and a down slope. If you calculate the value of your slope and you get the answer in a positive manner, then you know that this is an ascending slope. A positive slope or an upward slope. If your slope is 0 and the slope is 0, there is a constant X exists or Y exists. Now, how do we then calculate that slope to know in state of drawing the graph? We can find the slope because here we're looking at the slope by visualizing it, by seeing the pattern of the slope and we can make a conclusion on that. Because we can see the line that it is increasing as the value of X increased, the values of Y increased, it is decreasing as the values of X increased, the values of Y decreased. We can see that those two are constant. And we can also use the measures. By also having the two points, we can calculate what we call the slope. And the slope is just the ratio of the change in the value of your Y values to the change in the values of your X values. So we're going to take your 0.1 Y value and your 0.2 value and find the difference and also the 0.1 value or X value and the 0.2 X value and take the difference of the two. So how do we define it? The formula is Y2 minus Y1 and X2 minus X1. It is very, very important to identify your points with the X1 and Y1, like I did here. You can see that I've identified that this one is X1 and this is Y1. Always your first point has X and Y coordinates, so you cannot have X1, X2 as a point. No, it has to be X1, Y1, X2, Y2, they cross points with one another. So let's look at an example of how we calculate the slope. We will use also the other values that we have. So for example, if we are given here, we are told that this line passes through the two point and the point is 0 and 10 and 5 and 0. So we need to be able to label the point. Let X1 and Y1 be represented by the first point, which is 0 and 10 and X2 and Y2 be represented by the second point, which is 5 and 0. So we calculate the slope Y2 minus Y1, X2 minus X1. So because I've already identified my X1 and Y1 and X2 and Y2, it makes it easy for me to come and substitute the values into the formula. So our Y2, we're just going to take 0. Our Y1, it's 10 because we identified them from there with that statement. X2 is 5, X1 is 0. So it will be 0 minus 10 divided by 5 minus 0. And 0 minus 10 is minus 10, 5 minus 0 is 5. We need to simplify this to the lowest form. 5 can divide into 10. It goes into 5 one times and it goes 2 times into 10 and the answer will be minus 2. And that is how we find the slope. Let's go find the slope of our data that we have here, the original data that we have. We are going to remove the ink and calculate the slope. We know that the formula for the slope is, the slope is Y2 minus Y1 divided by X2 minus X1. So I need to go and label my points. My first point will be X1 and Y1, X2 and Y2. So now I can come and substitute into the formula. So my Y2 is 2. My Y1 minus 4 divided by my X2 is 4 minus my X1. This Y2 minus 4 is minus 2 divided by 4 minus 1 is 3. Therefore, my slope is equal to negative 2 over 3. So my slope is negative 2 over 3. And you can see that that is a negative slope as we saw with the graph. It also told us that this is a negative slope. So you are able to calculate the slope of that graph. This is your exercise. Find the slope of this straight line passing through these two points. And your formula is your, the slope is equals to, remember the formula has a minus. The formula has the minus. So you must also take into consideration the negative that is on the data point. So you need to first identify what you are given. Yes, what is your X1 and Y1? I was just going to ask if we could do this on our own quickly. You need to do that on your own. So you need to identify what, because this is your exercise. What is your X1 and Y1? And what is your Y2, X2, Y2? Let me know when you are done. Are you done or are you still busy? I'm done, but I think I'm wrong. Why do you think you are wrong? Okay. What is your, how did you identify your points? So minus 2 and minus 3. Minus 2 and minus 3 over minus. No, I want you to identify the points first. Oh, okay. So Y2 is minus 2 and minus 3. And X2 is 1 minus minus 2. Okay, you're not getting it. Yeah, so now I'm confused. No, wait, wait. Okay. I wanted you to first identify the points. If I say this is X1, this is Y1. Oh, sorry. Yes. And then X2, 1 is X2 and Y is minus 2. Yes. And then you can then come and substitute into the formula. Yeah. Yeah. So it's a minus 2 minus minus 3 over 1 minus minus 2. And there we, I think I got skews. Okay. So that will be minus 2 minus times minus. It's a plus. It's positive 3. So I got that right? 1 plus 2. Yes. So that is minus 2 plus 1 is? It's a minus 2 plus 1 is 1. But minus 2 plus 1 is 1. It's 1. And 1 plus 2 is? 3. And then it's negative. No. It's positive. Yes. Okay. So I was almost right. Thank you. I just got, because I've got the minus, but it's supposed to be the plus. So okay. This way I got confused. Okay. So if you have a cashier calculator, you can just do this on your cashier calculator. And it will, it will be, so it means I must stop sharing and share my entire screen. Your ladies get the same. Okay. So if you have a cashier calculator like this, that has a fraction button. You can just say, you will use this minus because it's not the, it's not the, the basic operation is the minus of the value. So minus 2 minus, and you put that into bracket minus 3 and close bracket and then go down. And it will be 1 minus open bracket minus 2 close bracket. Got it. And when you press equal, and that will give you the answer. So only for those who have a cashier calculator. I've got mine, but I don't have it. I'll look for it. Yeah. Otherwise then you'll have to calculate manually like I've done. Step by step so that you don't get anything wrong. Okay. So now we're done with calculating this loop. Let's then look at how we find the equation of a straight line. Now, before I get to finding the equation of a straight line, because I'm going to discard and I'm going to stop sharing. Again, because I want to go into my, because we're going to work with equations. So you should be able to manipulate an equation. And I hope what I'm going to share right now, you have already submitted your assignment. And there wouldn't be any problems with this. Okay. So this was one of your assignment, where they asked you to solve. Am I not sharing? Do you see my screen for some reason? No, we don't see it. Oh no. I just saw the chat now. Yeah. We see it now. We see it now. Okay. Okay. So because when we solve equations, like the straight lines and all that, you need to be solving for something. You need to be able to be comfortable to say, you know what you're doing. So let's look at this example where they asked you to solve for X for the following equation. And that is what you're going to be doing with when you find the equation of a straight line. You will need to solve for Y, which will be the subject of the formula. So now the first thing that you need to do is to remove or work with what we call bot mass, right? Remember the bot mass, bracket exponent or expression, division and multiplication. They've got the same priority. We work from left to right, addition and subtraction. Therefore, it means brackets comes before division and multiplication. And division and multiplication comes before addition and subtraction. When you have division and multiplication, you work from left to right. Regardless of whether multiplication comes first, you just work from left to right. When you have addition and subtraction in your sum, they start with a subtraction. And then comes addition, you just work from left to right. They've got the same priorities. So let's look at this question. It says solve for X. 2X plus 2 is equals to 2 times 2 minus X into bracket plus 6. So the first thing we need to do is bracket. So we need to get rid of the bracket. So it will be 2X plus 2 is equals to multiply with the 2. We distribute 2 inside the bracket. So it will be 2 times 2, which is 4. 2 times minus X will be minus 2X plus 6. We keep it as it is. Everything that has an X, we're going to take it over to the other side. So because we want to solve for X, it needs to move to the left. When it moves over, the sign changes. It's negative. So you will have 2X. It's negative. It will be plus 2X equals 4 plus 6. We also move 2 to the other side because it's positive. It will be minus 2X. 2X plus 2X is 4X is equals to 4 plus 6 is 10 minus 2 is 8. Because we're looking for X, not for X, we need to divide by 4. When it is dividing, we multiply. When it's multiplying, we divide to get rid of that. So 4 and 4 cancels out. You are left with X is equals to 4. 4 goes one time into 4 and it goes three times into 8. The answer is X is equals to 2. So that should have been your answer. And also with what we're going to be doing now, you will apply the same concept because we're going to be moving things around. Okay, so let's go and find out how do we solve the equation? What time does the class end? Oh, we started at 8. Oh, gosh. At 7, it ends at 8. I get lost with the times. Okay. So we're still on time. We started at 7. Yes. I'm thinking now I'm over time. I thought we started at 6. Okay. So equation of a straight line. So when we have that straight line, remember we have a line that looks like that. So this is our Y and this is our X axis and we have our straight line. So this straight line is represented by an equation. And that is what we call the equation of a straight line. And in your module, I guess you use the formula Y is equals to B X plus A or AX plus B. Let me see if I have the right values the way you will have it. A plus BX or BX plus A. Sometimes you write it as Y is equals to A plus BX or Y is equals to BX plus A. Now what is very important with this is that when you have your equation of a straight line, only the blue letters are actual numbers. Y and X remain as Y and X. We always going to be solving for Y. So the blue letters always are numbers. So how do we then make or find the equation of a straight line? We can find the equation of a straight line. If you are given two points, you can calculate the equation of a straight line. There are many ways of finding the equation of a straight line, but in B and U, you have a formula. So we can also, based on the example that we're going to be doing, we can determine which values of X and Y will that be? It's the same example that we had previously. In your module, your formula is Y minus Y1 divided by X minus X1 is equals to the slope. You can see that the left hand side is the same as what we've calculated as a slope, right? Y2 minus Y1 divided by X2 minus X1. And because we want to end up with an equation that looks like this. Therefore, it means every way we have X1, Y1, X2, Y2, we are going to substitute it with the actual value and solve the equation by making Y the subject of the formula. You remember last time we met, we spoke about the subject of the formula. So previously, we already identified that our X1 and Y1 is 0 and 10, and X2, Y2 is 5 and 0. So we can go into the formula and substitute. So where we see Y1, we put, where we see X1, we put 0. Y2, 0 minus 10. X2 minus X1, 5 minus 0. And we have calculated this previously. We know that it's equals to minus 2. So now this side on the left hand side, we have Y minus 10 divided by X minus 0. So this can also be the same as Y minus 10. Y minus 10 divided by X because X minus 0 is the same as X equals to minus 2. So we need to solve this. We can take X minus 2 to the other side. Or we can multiply because it's dividing. So because it's dividing, we multiply. So this will be minus 2 X and we will be left with minus 10 on the left. And we want to get rid of minus 2. It is subtracting when it goes over, it will be positive. So it will be Y is equals to minus 2 X plus 10. That will be the equation of a straight line. As you can see, our blue are represented by numbers. The X and the Y stays as they are. So in terms of this equation as well, if I keep the 0, you're just going to take the X minus 0 multiplied on the other side. Put it in the bracket when you move it over because sometimes this will be a number. Make sure that you move it inside the bracket and then distribute the 2 minus 2 into the bracket. So it will be minus 2 times X is minus 2 X minus 2 times 0 is 0. And move 2 to move minus 10 to the other side. It will become positive 10. As you can see only the blue letters A and B are numbers and Y and X stay as they are. And that's how you will find the equation of a straight line. So let's look at an exercise or an example. Let's do one more example. I'm going to use our points. You still remember the points that we used in our example previously, which were 1 and 4 and 4 and 2. I'm going to use those ones. Actually we include a new slide, a blank slide. We have our points 1 and 4 and 4 and 2. That's what we had. So if the question is, we need to find the equation of a straight line. We know that the equation of a straight line is Y minus Y1 divided by X minus X1 is equals 2. Y2 minus Y1 divided by X2 minus X1. Now I need to identify this is my X1, Y1, X2, Y2. It's very important to do that before you can substitute into the formula. So our Y stays as it is minus our Y1. We said it is 4 divided by X minus X1. We said it's 1 equals Y2 is 2 minus Y1, which is 4 over X2, which is 4 minus 1. X1, you are left with Y minus 4 divided by X minus 1. And 2 minus 4 is 2 over 3 and it's minus 1. So now you can see that I have X minus 1. So I need to take X minus 1 and multiply it onto this equation that we have here. I'm going to use the next. So I'll be left with Y minus 4 on the left and I'm going to multiply 2 over 3 by X minus 1. And solve, distribute, distribute. So Y minus 4 will be minus 2 times X is minus 2 X over 3. Minus times minus is positive 2 times 1 is 2 over 3. And that is not the end because I need to get rid of minus 4. Minus 4 is subtracting so it will be Y is equals 2 minus 2 over 3 X plus 2 over 3 plus... Oh, now I've got a fraction here. I need to solve a fraction. Do you know how to solve the fraction? So if I have 2 over 3 plus 4, this is a fraction. I can put it over 1 because I'm adding, when you add or subtract, they need to have common denominator. Since they do not have a common denominator, I'm going to find the common denominator. That would be that value that can 3 and 1 divide into and not leave it remainder. It's 3. So 3 is the common denominator. 3 goes how many times into 3? It goes one time. 1 times 2 is 3. 1 goes how many times into 3? It goes 3 times 3 times 4. It's plus 12. 2 plus 12, it's 14 over 3. And because it is 14 over 3, it is a... And we call this... We call 14 over 3 a improper fraction because the value at the top, which is your numerator, it's bigger than the value at the bottom, which is called the denominator. And since your denominator is 3, we say 3 goes how many times into the numerator, which is 14, so it goes 3, 6, 9, 12. So it will go 4 times and the remainder will be 2. So this will be 4, 2 over 3 because 3 times 4 is 12 plus 2 is 12. And then that will be the answer that you will write there. Y is equals to minus 2 over 3 X plus 4, 2 over 3. Or sometimes if you will look at the answer, if the answer they left it as an improper fraction, you can leave it as an improper fraction. Okay, so let's do more exercises that you guys can practice with. Here is your first exercise. Determine the equation of a straight line that passes through these points. I will graciously write you the formula. Y minus Y1 divided by X minus X1 equals Y2 minus Y1 divided by X2 minus. Let me know when you're done. I'll give you 5 minutes to try it out. Are you winning? Are we done? Yes. Ma'am, I'm so busy. I'll give you more time. Thank you. Can you bring up that other screen again please? I'm trying to, something is, I got my, sorry, it kicked me out. I don't know why. No, it's not. Are you able to see the screen? Yes ma'am. You will let me know when you're done. And please also remember to complete the register. I'll repost it in case you join this session. I'm done. Okay. I'll wait to hear about the others. I'm done, ma'am. Yeah. I'm done. All right. Thank you. What is your X1 and Y1? X1 is 3. You go, you go. We're into it. So 3 is X1. And the minus 2 is Y1. And then 5 is X2. And minus 6 is Y2. Let's substitute into the formula. So Y minus. Brackets minus 2. Over minus 5. No, 3, sorry. Equals minus 6. Okay. Minus. Bracket. Minus 2. And then over 5. Minus 3. That's 12. I'm done now. Minus times minus is positive, right? Yes. That would be Y plus 3. Over X minus. That's 2, not 3. Equals minus 6 times minus 6 minus times minus 2 will be minus 6 plus 2. Over 5 minus 3. So let's solve the right-hand side. Minus 6 plus 2. It's minus 4. 5 minus 3 is 2. On the left, you are left with Y plus 2 over X minus 3. Now we need to get rid of X minus 3, so we multiply. On the left, you'll be left with Y plus 2. Equals minus 4 over 2 times X minus 3. Distribute minus 4 over 2. We could also already from here solved because 2 goes one time into 2 and it goes 2 times into 4. And this would have been left with minus 2 as the answer, right? Because it's minus 2. And we distribute 2. We distribute minus 2 into the whole bracket. We have Y plus 2 equals minus 2 times X. It's minus 2X minus 2 times minus 3. It's plus 6. We move 2 to the other side. It will be Y is equals to minus 2X plus 6 minus 2. Y is equals to minus 2X plus 6 minus 2 is equals to... 2X minus... ...minus 2, which is option 4. This is so cringey. Okay, but it's fine at this end, I can see where we draw. Okay, so I have another one for you to do. We still have 20 minutes, so you still have more to do. Wait, find the equation of a straight line passing through those two points. Y minus Y1 over X minus X1 by 2 minus Y1 over X2 minus X1. Maybe if you can get this one up to the end. Let me know when you are done. If you are stuck, also there's no problem with telling me that you are stuck so that we can use the time effectively by me helping you answer the question. I'm done and I'm hoping for the best. Okay, are you all done? It seems as if you are all done, we can then do... Okay, so our X1 and Y1. I'll just write them for us. X1, Y1, X2, Y2. Who wants to do it? No one? I'm going to do it then. My turn. I just did it earlier. Okay, Juliet, come on now, focus. I'm not going to try, I'm not going to. Okay, so I'll do it for you. Okay, so you will do all the calculations. If it's not number two, then I don't want to do it. Okay. X minus X1 is minus 2. Equals. Y2 is 2 minus Y1 of 3. Over. X2 is minus 3 minus X1 of minus 2. So we'll be having Y minus 3 over X minus 2. X minus 2 minus... Where do I get the minus from? 2 minus 3 over minus 3, minus minus, it's positive 2. So we can solve the right-hand side. Y minus 3 over X plus 2. On the right-hand side, what is 2 minus 1? Oh, sorry, 2 minus 3. Minus 1. It's minus 1. Minus 3. Plus 2 is minus 1. It's minus 1. So this side we can say also it's the same as positive 1. Minus 1 divided by minus 1 will give us 1. So the left-hand side, we will have Y minus 3 equals and then we multiply 1, which is the answer we get from minus 1 divided by minus 1. So we're going to multiply it with X plus 2. X plus 2. And Y minus 3, we distribute 1. It will be X plus 2. Take 3 to the other side. Y is equals to X. Plus. Plus 2. Plus 3. Y equals X. Plus 5. So it's number 4. I got it right? 4. Okay, I see we are going wrong. Okay, okay. Okay. All right. So we left with how many more minutes? Okay, let's do another one. Okay, which is the last one? Which is the last one? So we also have our X1, Y1, X2, Y2. I will start with the formula, X1, Y1. Sorry, Y1, Y minus Y1. X minus X1 equals to Y2 minus Y1. Y1 over X2 minus X1. See, if you can get this, I will give you the values. Minus 7 over X minus 2 equals 4 minus minus 7 over 1 minus 2. Let's see if you can get this one. I'm done. Okay. You did get the answer. Yes, I got the answer. Let's just say which answer I got. Yes, you can say. We can do it together. Okay, let's do it together. But other than chariot and didli, are you guys done? Yeah. Okay. So after that step, 4 minus the minus 7 in brackets equals to 11. And 1 minus 2 equals minus 1. And then we write down Y minus Y plus 7. And then on the other side, we take X over 2, 11. Okay. So we write Y plus 7 plus 2 equals to 11 minus 11 times X minus 2. Which gives us then minus 11 plus 22. Then we're taking the 7 over and because it's a plus, it's going to be a minus on the other side. So it's minus 11 X plus 22 minus 7. And then Y equals minus 11 plus 15. So the answer is number 2. And that concludes today's session. So. I got that one right. Yes! With minus and the minus and the minus that I got it. Yeah. Julia, you're very quiet though. You okay? I'm good, thanks guys. Just to recap on what we've done today. We've learned how to draw the straight line on the set of two Xs that when we are given two points, we can draw the straight line. Can also determine the slope of the graph or the slope of the line by looking at the line, whether it's positive or it's negative. And we can also calculate the slope. Remember the slope is your Y2 minus your Y1 over your X2 minus X1 gives you the slope and it will also tell you whether the slope is negative or positive. Then we also learned how to find the equation of a straight line by using the formula Y minus Y1 over X minus X1 equal Y2 minus Y1 over X2 minus X1. So these are just the basic things that you have learned. So sometimes in your module, they might give you questions in a wait format. You just need to read the question carefully and map out your points. So they might give you things like if the rent, sorry, they say a quantity and cost or price. Let's put it price there. Quantity and price. So the quantity will correspond with the price. So if they say if I buy 200 CDs for 100 rent, therefore my 100 CD will either, they will have told you that which one is your X, which one is your Y, your 100 CDs for 100 rent. And the next one, they say if they increase the number of or the quantity to 150 and then the price also increased to 120, you should be able to link that quantity with the price so that you can create your X and Y. So it's not always that you will get questions like this straightforward, but they might be a little bit trickier. And we can always discuss them as and when we get those type of difficulties throughout the sessions. And now I'm going to hand over back to you to tell me what is it that you want us to discuss in detail next week. That is the topic that you for next, not that, not that. For next session. Do you have a topic in mind? All my stuff made. We get back to you. I know that whatever we did now. She's going to do it again. I got that one at least. I'm just a member of the negative and a negative in the part of the positive. All of those negatives and positives, but the straight line story is in assignment four guys. So yeah. What else is in assignment four that you guys are struggling with? So I know. I'm looking at it. So I know. It's interesting. Basic financials. It is basic financials. We just like chapter. Okay. The straight line is chapter six. And then the basic financial is chapter seven. So that is our next one, which is you, the ninth, which is this coming. Wow. Did you check the date that says the thirtieth now? Is it? I don't know. I think it's the thirtieth of September. Well, just check again. But on this actual assignment, it says the ninth. Yeah, ma'am. Let's do this interest compound stuff. Let's do that next week. Okay. We will look at the financial met next week on the 12th. And how to work this calculator. I was looking at the basic financial calculations. That's chapter seven, right? Yes, yeah. Interest and stuff. Because that is in this assignment that is due for now. Why? Why did they give us this option as a subject? I don't know. Really? You do a good job. You do a good job, ma'am. Really, really, ma'am. You explained it. You know what? For my laws, okay. For my three assignments of four, right? I've got like 65% 65. Yeah. I'll see what I'll do with this one. You're going to pause. Don't worry. We're all going to pause. I don't want to do this thing over again. I don't want to. I don't want to. And once you're over 45, that's now me talking for myself, right? Thank you. Thank you. Thank you. Thank you. Thank you. Thank you. Thank you. I dropped it long time ago. I think it was 91 or something like that. I don't know what's going on. You know, ma'am, I understand when you do it with me, with myself. Yeah. It's fine. Remember, assignments are there to help you prepare for your for your exams. So the more you practice, the more you get used to this. So the time we do your financial meds you would have a day before you close the date if your assignment is due on the 18th, but do not worry because we're working towards you making sure that you pass your exam, right? Thank you so much. That's my goal. That final final end product which is passing that exam. So we will do financial meds and then the following week we will continue with the financial meds because I wouldn't have covered everything you will need for financial meds because financial meds include simple interest, simple discount, compound interest, and annuities, and then amortization. What amortization? Yeah, I think it's part of your module as well, so you must check. Why? I asked how many assignments do you guys get? This is assignment four that you're talking about, so do you still have assignment five? Yes, ma'am. Okay, then probably in your assignment five it will include annuities and amortization. Annuities are like payments. So if you own a house, you're paying a bond, we do amortization of your bond. It's like a financial statement of your company, yeah, we talk about amortization. If you own a car, you do get this monthly statement that tells you how much you owe, how much you have been paying all those things, even on your loan, your ordinary loan, you do get the financial statement that shows you your transactions per month, the interest paid. So all those things, it's the same thing that we will be doing in this. But anyway, I will see you on Monday when we discuss financial meds, interest and compound interest. That's what you want. Yes, ma'am. We'll do that. Thank you very much. Thank you. Have a good evening, folks. Good evening. You too. Bye. Thank you. Bye. Thank you. Bye. Bye. Girls, don't go yet. What's up, Linda? What's up, Linda?