 I think it'll be helpful for us to do this one for everyone, you know? Okay, so let's try this mechanism now. So we talked about it, remember. Of course, how do we get these products from this starting material? We know that ozone is going to cut this double bond in half, cut this alkene in half, and again if you want to, you can put those H's there to make sure, right? And this DMS remembers these reductive conditions, okay? Remember DMS is this molecule here, dimethyl sulfide, okay? And when you do reductive conditions, you get ketones and aldehydes out. So it just cuts it in half and puts oxygens there, okay? So but it's not as simple as that in the mechanism, okay? So remember, we add this first and then this second. So I'm going to erase all of this stuff and then I will write the structure of ozone. Ozone's got that permanent dipole on it. In fact, that's the driving force for the reaction. This is very nucleophilic oxygen here. So what'll happen is actually, so we learned about these 1, 3 cycloadditions, the first step. So again, you know, you learned this reaction in an organic one, right? But the mechanism, you wouldn't be able to understand until we did that, the last chapter, okay? It's when we talked about the cycloadditions. So what'll happen here, that'll attack there, and then this alkene double bond will attack that oxygen there, and the driving force for that will be the relief of that positive charge on that oxygen there. So when we do that, we're going to make this intermediate. This intermediate is called amylosonide, and he was actually talking about the second intermediate, which is called a trioxide. So we'll talk about that in a second, yeah. Okay, so then what it'll do here is do a retro 1, 3, but instead of breaking these carbon-oxygen bonds, it's going to break this carbon-carbon bond here, okay? And so what we'll make is the driving force of that carbon-carbon bond formation is going to be the fact that these electrons here are going to come down and make this double bond here, okay? And again, you could start from this side or from the other side. Either way would be fine, okay? Again, this is a reaction where all the bonds are being broken, it's a concerted reaction, all the bonds are being broken and formed at the same time. So it's the first one, by the way. All of these cycloadditions, as you know, are, okay? So then we'll make this other intermediate, in this case, we made it the aldehyde, being the, what we call the creaky intermediate. That gives, that looks like what these arrows are saying, right? But what'll happen here, so now we have one of our products, but we don't have the other one, right? This one's called the creaky intermediate, I don't know if we had said that earlier, but this negative charge here and this delta negative charge here don't like each other. So what you'll do is have kind of a rotational change here with this aldehyde intermediate flipping around. So kind of what we'll do, rotation like that, and is it okay if I just erase and then put it back? I mean, does that really matter though, you just draw it the right way? Well, you draw it the right way, so it'll be ready for another one's three-cycloaddition. I mean, yeah, if you wanted to, if you're doing this mechanism on a test, just draw it the right way, you know, because I understand that, but I just wanted to emphasize what's going on. Yeah, exactly. So we've got that now, okay? So this in particular, if you were wondering, is called the creaky intermediate. And then again, barynucleophilic oxygen, electrophilic carbon, so we're going to have another one-three-cycloaddition so you get that. Again, so this is what I was talking about, if you have on your ketone or if you got an aldehyde that is not from aldehyde that you're making, two different substituents, you're going to have a stereocenter here and here, okay? So in both of these, there's not two different substituents, though. And we were calling this the trioxaline, not that you need to know any of these names for this, okay? But just in case somebody tells you, in fact, another name for this is carbonyl oxide. So just in case you hear it sometime, okay? So one-three, retro one-three, another one-three-cycloaddition. And this is where it gets stuck, okay, after the first step, after you put your ozone in there. In fact, your solution will kind of turn blue when, and that's how you know you've got, you know, your ozone in there and it's all reacting, okay? And then it gets stuck here and then you've got to add your DMS to it, okay? So remember, DMS looks like this, dimethyl sulfide. It's very oxophilic sulfur is. It likes to make sulfoxides from sulfides, okay? So again, like I was saying in class, I would probably prefer to attack this oxygen here because it's less sterically hindered than that oxygen there. But honestly, I probably wouldn't take off anything if you attacked either one of them. And what would happen here is you would attack that oxygen there. These electrons will go there, like that. These electrons will go there and these electrons will go there, okay? So when you, if you follow all those electrons around, what you should end up getting is the ketone from here, okay, the aldehyde from here, the top portion, so we'll draw it from there. And then here, right, you've got dimethyl sulfide reacting with that oxygen. So what you're going to have is dimethyl sulfoxide. And remember, well, sulfur with three bonds of two electrons likes to have a positive charge. And you know, you knew that anyways, but you also know that that double bond, that pi bond, it's not easily overlapped between those two atoms because sulfur is very big relative to oxygen. So the preferred resonance structure is like this, yeah. So it comes directly from this mechanism, you know, so you don't have to, you know, like kind of remember how the bonds are supposed to be. But again, it's this part is I'm not so concerned about, you know, I mean, and honestly, I just, I want you to know this stuff. The mechanism is important for you guys to understand how it all comes from, okay? Do you have any questions? Do you have any questions? The only confusing part is that it creates, like in the mid-step when it's carbonyl oxide, it's like, you've created, it looks like it's almost done to go back and do that. I know, right? Yeah. So the thing is, is there was a lot of controversy about this mechanism, but apparently it's, you know, been radioisotope labeled and, you know, they figured out that if you radio label carbon 7, or oxygen 17, you'll find that it goes through this set of intermediates. So they argued about whether or not it would. Yeah. So they did argue about that, exactly what you're saying is why would it do that, you know? Okay. But yeah, it's interesting. It's kind of funny how education works. Yeah, it is. Well, we had to figure out, we had to see the results of the experiment before. And that's how all organic is. We got to see the results before, I mean, sometimes we can predict, you know, obviously, you know, that's what we're doing in organic, that's the point, you know? But if there's something totally new comes out, you got to figure out what you're working with, you know? So and again, like we said, if you do oxidative conditions, which we'll talk about in next chapter, this is reductive conditions. Oh, the other thing you can use, I forgot to tell them. You said that though. Yeah, I said it in class, but I'm on the video too. You can use zinc instead. Do the same thing, grab hydrogen. Yeah. And I guess there was another question in class, why did the DMS wait till here to attack? You know, why tell those stuff? We didn't add it. But it's because we haven't added it yet, okay? This was all one. It's all against it here with the ozone by itself, okay? The second step is, yeah. You wrote it in multiple steps, but it would happen relatively quickly. Well, so no, it takes this many steps, exactly that many steps. One meant from there to trioxalate. Yeah, it'll take one, two, three, four steps. And then the next step is that. I meant experimentally, like in the lab. Yeah, in the lab you're going to add that thing. Yeah, mechanistically it's going to take this many steps, but yeah, in the lab it's real easy. You just bubble some ozone through your solution, wait for 20 minutes, 10 minutes, you know, until it turns blue, and then you know it's cool. And then you add some DMS, and then you go and roto-vap it down, because you usually do this in DCM, you know, so everything is gone. Then how do you separate those two, and how do you want the albac? Well, this thing has a very small boiling point, very low boiling point, so they roto-vap away too. You usually don't want to be making formaldehyde, you know, I mean why make that stuff, you know what I'm saying? So usually it's what this part that you're more interested in, you know, but those are all good questions, you know. That's practical questions actually, which is the real point, you know, any more? Okay, cool.