 Okay, let's do this mechanism that you already know, the dibromination of cyclohexene. Why are we doing this? Because we're going to compare it to the quote unquote bromination of benzene that doesn't happen. But anyways, just to recall since you didn't, you haven't seen this reaction in a while, let's do the mechanism of it. So bromine looks like that, right? So what's going to happen is once this gets close to this pi bond, what you're going to have is a dipole form and induced dipole, right? So that's going to make this bromine partially positive, this one partially negative because of the negative charge here. So what's going to happen, of course, is this bromine here is going to become electrophilic, as you already know. So once that becomes electrophilic, it's got all those, you know, it's a huge atom. So it's got all those empty orbitals, you know. So what's going to happen is once that becomes electrophilic, it's going to attack like that. And then that's going to break that bond there and also form that bond there. You do that. I could draw either one of the two enantiomers. I'll draw the, I don't know, just for fun, we'll draw the one that goes back to positively charged bromine or a bromonium on it. Because we have no charge over here, we're going to have to have no charge over here, right? As you know that from Jim, you know, VR minus. And then what's that going to do? The least favorite reaction, the SN2 reaction. Backside attack, right? OK. So when that happens, we're going to get a di-bromide. Plus, it's an enantiomer. Of course, this bromine could have attacked from the other way. The ones we do. So the product is actually an issue. So when we react cyclohexene with bromine, it reacts. That's the whole point, right? And if we compare that to the reaction of benzene, right? This is cyclohexene, right? If this was cyclohexatriene, right, we would expect to be, you know, one, two bromines there, one, two bromines there, one, two bromines there. So hexabromines, right? But what happens when we react this with VR2? No reaction. Why? Because it's super stable, OK? And that's what we're going to get into now, OK? So aromaticity brings overly stable structures, OK? It gets overly stable structures. All right, any questions on that? I know we haven't gone into it very much. At least the mechanism of the cyclohexene bromination.