 Hello and welcome to the session. The given question says, prove that the 0.0055 and minus 55 are vertices of a right isosless triangle. So let's start with the solution. Given points are 0.0055 and minus 55, denoting these three points by A, B and C. Now we know that in a right triangle, suppose this is a right triangle and this is the hypotenuse, this is base and this is the perpendicular, then we must have h square is equal to p square plus b square, that is the square of the hypotenuse is equal to the sum of the squares of base and perpendicular. So here first we shall find the distance AB, BC and AC, then we shall verify that whether the square of any one side is equal to the sum of the square of other two sides. First let us find AB and for that first let us learn the distance formula which says for two points A with coordinates x1, y1 and B with coordinates x2, y2 the distance AB is equal to the square root of x2 minus x1 whole square plus y2 minus y1 whole square. So AB with the help of distance formula is equal to 5 minus 0 whole square plus 5 minus 0 whole square. So this is equal to root over 25 plus 25 which is further equal to root over 50 and this is further equal to 5 root 2. Now let us find the distance BC, BC is given by square root of minus 5 minus 5 whole square plus 5 minus 5 whole square, this is equal to root over 100 plus 0 which is equal to root over 100 and its value is equal to 10 and now let us find AC is equal to root over minus 5 minus 0 whole square plus 5 minus 0 whole square and this is equal to root over 25 plus 25 which is equal to root over 50 and this is equal to 5 root 2. Now let us find first AB square plus AC square this is equal to 5 root 2 whole square plus 5 root 2 whole square and this is equal to 50 plus 50 and this is equal to 100 and 100 can be written as 10 square and 10 is the side BC so this is equal to BC square. So this implies that BC square is equal to AB square plus AC square and so we have in a triangle ABC the side BC square is equal to AB square plus AC square so this implies angle A is of measure 90 degree and also here we have side AB equal to AC since both the sides are equal to 5 root 2 and this is also 5 root 2 and since for the given three points Pythagoras theorem is satisfied therefore we can say that the given three points are the vertices of a right isoslip triangle also says AB is equal to AC hence the answer is the points 0 0 minus 5 5 are the vertices of isoslip triangle so this completes the session by intake care.