 Hi, and welcome to the session. I am Shashi. Let us do one question. Question is, show that matrix A is equal to 0, 1, minus 1, minus 1, 0, 1, 1, minus 1, 0 is a skew symmetric matrix. First of all, let us understand a square matrix A is said to be skew symmetric matrix if A transpose is equal to minus A. Or we can say transpose of A is equal to negative of A. This is the key idea to solve the given question. Let us now start with the solution. We are given A is equal to matrix 0, 1, minus 1, minus 1, 0, 1, 1, minus 1, 0. First of all, let us find out A transpose by interchanging the rows and columns of A. So, we get A transpose equal to 0, 1, minus 1, minus 1, 0, 1, 1, minus 1, 0. We can also write A transpose equal to minus 0, 1, minus 1, minus 1, 0, 1, 1, minus 1, 0. We can see this matrix is exactly same as matrix A. So, we can write A transpose is equal to minus A. Now, since A transpose is equal to minus A, so given matrix A is our skew symmetric matrix. Hence proved this completes the session. Hope you understood the session. Take care and goodbye.