 Hi and welcome to the session let us discuss the following question the question says in a single throw of three dice determine the probability of getting a part is a total of five b part is a total of at most five it's now begin with the solution now when three dice are thrown simultaneously of possible outcomes three equal to into six into six that is two one six a part we have to find the probability of getting a total of five this given r that means in the first time we get one in the second time we also get one and in the third time we get three b one one favorable able to this table that means a total of five is okay and these times is equal to six hence are required probability for two six by two one six and I'll simplify this we get one by 36 so this is our answer to the a part let's now move on to the b part in b part we have to find the probability of getting a total of at most five able to this event of one three one three equal to number of outcome favorable to this even that is ten upon total number of outcomes that is two one six on simplifying this we get five five one zero eight so this is our answer to the b part b of getting a band by 36 and probability of getting a total of at most five is five five one zero eight these are our required answers so this can be explained by and take care