 Hello and welcome to the session let's work out the following question. It says draw a circle of radius 6 cm from a point 10 cm away from its center construct the pair of tangents to the circle and measure their lengths. So let's now move on to the solution. We'll do the construction and side by side we'll be writing the steps of construction. The first step is to draw a circle with center O and radius 6 cm. So we have drawn a circle with center O and radius 6 cm. Now the next step is take a point P at a distance of 10 cm from O. So we have taken a point P 10 cm away from the point O. Now the next step is join O P bisect O P let M be the midpoint of O P. So we have joined O P and we have bisected O P and it is bisected at the point M. Now the next step is taking M as center and MO as radius draw a circle let it intersect the given circle at the point Q and R. So we have drawn a circle taking M as center and it intersects the given circle at the point Q and R. So let this point be R and let this point be Q. Now the next step is join PQ and PR. So we have joined PQ and PR then PQ and PR are the required two tangents. For justification we are justifying that PQ and PR the PR are the tangents. What we do is join OQ then angle PQ O is an angle in the semicircle that is angle PQ O is 90 degrees right. Since it is angle in semicircle therefore it is 90 degrees as we know that angle subtendent in a semicircle is of 90 degrees. So this is 90 degrees which means OQ is perpendicular to PQ. And since OQ is the radius of the given circle PQ has to be a tangent to the circle PQ has to be a tangent to the circle. Similarly PR is also tangent to the circle. So we have done the construction and this completes the question and the session. Bye for now. Take care. Have a good day.