 So let's do this problem for your acid-base equation, let's write the net ionic equation for this acid-base reaction. HCl plus NaOH goes to water and NaCl. So this is the molecular equation. And we want to figure out the net ionic equation, but before that we've got to do the total ionic equation. So we're writing out the total ionic equation. Just take this and anything that says aqueous, you break it up into its ions. So HCl is aqueous, so two ions are going to be H plus. This is not aqueous, this is liquid, and you're going to keep it together. NaCl, that's aqueous, NaCl, squeeze that ion in. And now all you've got to do for the net ionic is take the things on both sides that are the same and cancel them out. So those are both spectator ions. So we'll take the spectator ions and cross them out. So H plus, we see it over here, but we don't see it over here. So it's not a spectator ion, so we'll put that in the equation. Cl minus, we see it here, and we see it there, right? So it's a spectator ion. Just cancel that out, and we don't put it here. So Na plus here and here, so it's also a spectator ion. So we cancel that out, don't put it in the net ion. OH minus, well I don't see it over here, so we've got to put that in here, because it's not a spectator ion. Of course, H2O liquid isn't an ion at all, right? It's an ion has to have a charge. So the net ionic equation for this neutralization reaction is H plus A quidus plus O H minus A quidus goes to H2O liquid.