 Hello friends, let's discuss the following question. It says, find the equation of the line parallel to y-axis and drawn through the point of intersection of the lines, x minus 7y plus 5 is equal to 0 and 3x plus y is equal to 0. So we have to find the equation of the line which is parallel to y-axis. That means its equation is of the form x is equal to a that means the value of x from which this line passes through and we are given that this line passes through the point of intersection of these two lines. So our aim is to find the point of intersection of these two lines and since the line is parallel to y-axis the equation of line will be x is equal to a where a will be the x coordinate of the point of intersection of these two lines. So let us now proceed on with the solution. The given two lines are minus 7y plus 5 is equal to 0 and 3x plus y is equal to 0. Now we have to find the point of intersection of these two lines and thus we can find by solving these two equations and from 2 y is equal to minus 3x. Now put y is equal to minus 3x in 1. So 1 implies x minus 7 into minus 3x plus 5 is equal to 0. This implies x plus 21x plus 5 is equal to 0 and this implies 22x plus 5 is equal to 0 and this implies x is equal to minus 5 upon 22. This implies y is equal to minus 3 into minus 5 upon 22 that is 15 upon 22. So the point of intersection of the lines is minus 5 upon 22 and 15 upon 22. Therefore equation of line y-axis passing to the point of intersection of the given lines which is minus 5 upon 22 and 15 upon 22 is equal to is given by x is equal to minus 5 upon 22. Hence the required equation of line is x is equal to minus 5 upon 22. So that's all for the session goodbye and take care.