 OK, so this is going to be an example of pumping power. And we're going to use water for now. But essentially, the only difference is the density, so for this equation. And so if you had a fluid that was denser or less dense, for example, like oil, it would be pretty comparable to this calculation. So power is equal to basically the volumetric flow per unit time times the density of the fluid times Earth's acceleration due to gravity on Earth, which is 9.81 meters per second. You may recall from physics class, potentially even in high school, times the head of the pipe that you're in. This is the distance, and that's essentially it. And you have to just be careful of the units. So for example, we have fluid that's traveling 1 meter cubed per hour. That's the volumetric flow rate. And the density of our fluid is water, so 1,000 kilograms per meter cubed. The g is 9.81 meters per second squared, acceleration. And let's pick a distance of 10 meters. We want to pump our fluid up 10 meters, essentially. What we end up with, 1 meter cubed per hour times the density is 1,000 kilograms per meter cubed. And those cancel times per second squared. And oops, meters did not cancel with anything yet. Sorry about that. And our distance is 10 meters. So you can see here in the numerator, we have kilograms meters squared per second squared. There's kilograms meters squared and second squared. Kilogram meters squared per second squared is equal to a dual unit of energy. We also have time still in the denominator over here. So if we have joules per time, that's power. But we need a conversion factor. We need to say that 1 hour is 3,600 seconds. So then we can cancel hours. And we're left with seconds and a joule per second. A joule per second is equal to a watt. So we get it in watts if we do that. So when we multiply all of those pieces together, in handy-dandy calculator here, 1,000 times 9.81 times 10 meters divided by 3,600. Or I just typed in my calculator. For all I know, you've actually already done this quicker than I have. You end up with 27.25 watts as your pumping power to achieve that flow rate of 1 meter cubed of fluid per hour. That's the continuous pumping power required to do that. So just real quick here. If we wanted to know the energy say over a 4-hour period, 27.25 watts for 4 hours is 109 watt hours, or 0.11 kilowatt hours of energy. So in this case, we weren't pumping too fast. 1 meter cubed per hour is not that high of a rate. We weren't pumping it very far either. Only 10 meters up against gravity. So it's a pretty low cost, low energy result. But as you scale that up over, say, an entire multiple acres of collectors or whatever, you would definitely see high pumping costs. Thanks.