 Hello and welcome to the session. In this session we discussed the following question which says Construct an isosceles triangle whose base is 4.8 centimeters and its vertical angle is 80 degrees We move on to the solution now We will construct this triangle step by step Now we are given that the base of the isosceles triangle is 4.8 centimeters so in the first step we draw a line segment Say BC equal to 4.8 centimeters This line segment BC is of measure 4.8 centimeters Now in the next step we make angle CBX Equal to 80 degrees that is the measure of the vertical angle And we draw this angle below The line segment BC So this angle CBX is of measure 80 degrees Now in the next step we make Angle X B Y equal to 90 degrees So this angle X B Y is of measure 90 degrees Now in the next step We draw the perpendicular bisector PQ of BC This PQ is the perpendicular bisector of BC such that PQ intersects B Y say at point O Then in the next step with O as the center and radius O B We draw a circle So taking O as the center and radius O B we have drawn this circle which is intersecting PQ at point A Now in the next step We join AB and AC Now we have joined AB and AC so this triangle ABC is the required triangle with the side AB equal to the side AC that is it is an isosceles triangle and Angle A equal to 80 degrees that is vertical angle is of measure 80 degrees So this completes the session. Hope you have understood the solution for this question