 Welcome to the session. Let us discuss the following question. The question says, construct a triangle A, B, C in which B, C is equal to 6.5 centimeters and A is equal to 60 degree and altitude A, D is equal to 4.5 centimeters. In the first step, we will draw a line equals to 6.5 centimeters. In B, C which is equal to 6.5 centimeters. Step, we will draw angle C, B, X equals to 60 degree. The angle C, B, X which is equal to 60 degree. Stone 90 degree. A B, X which is equal to 90 degree. Now, bisection on B, C. This is the perpendicular bisector M, N of line segment B, C and it intersects B, Y at a point O and let D be the point of bisection on B, C. Center will draw a circle O as center from D P distance of 4.5 centimeters. P which is at a distance of 4.5 centimeters from point T. We will draw A dash intersection A dash with the circle which is parallel to V, C. Now, in the last step, we will join these are steps of hand structure. I hope you understood the solution well.