 Hello and welcome to the session. My name is Mansi and I'm going to help you with the following question. The question says, find the following integral a x square plus b x plus c dx. Now let us start with the solution to this question. Now we can write integral a x square plus b x plus c the whole into dx as integral a x square dx plus integral b x dx plus integral c dx. Now this can be written as, now a being a constant comes out of the integral sign as it is and we have a into integral x square dx plus b into integral x dx plus c into integral 1 dx. This is equal to a into now integral x square dx will be x raise to power 2 plus 1 that is 3 divided by 2 plus 1 that is 3 plus b into x raise to power 1 plus 1 that is 2 divided by 2 plus c into 1 is same as x raise to power 0. So x raise to power 0 plus 1 is x divided by 1 plus some constant c 1. Now this we do because we see that integral x raise to power n dx is given by x raise to power n plus 1 divided by n plus 1 plus some constant c where n is not equal to minus 1. So using this we get this. Now here we see that it is very important to put a constant sign here because when we find differentiation of this entire term we should get this entire thing. We see that differentiation of c 1 is 0 but differentiation of a x cube by 3 is a x square of b into x square by 2 is b x of c and so on. So every time we find an integral we put a constant term along with it so say small c. So to this question is a x cube by 3 plus b x square by 2 plus c x plus c. So this is our answer to the question. I hope that you understood the question and enjoyed the session. Have a good day.