 Hello and welcome to the session. Let's discuss the following question. It says 11 balls are serially numbered and placed in an order. Find the probability that a ball drawn will be odd numbered ball, even numbered ball, prime numbered ball. So let's now move on to the solution. And given that the total number of balls is 11, we have to find the probability that a ball drawn will be an odd numbered ball. So odd numbers between 1 to 11 and 11 and how many are there? 1, 2, 3, 4, 5, 6. So the probability of drawing an odd ball will be 6 by 11 as we know that the probability of any event E is given by the number of outcomes favorable to E upon the total number of outcomes. Now here E is the event of drawing a ball numbered odd numbers between 1 to 11. So the probability is 6 by 11. Second part we have to find the probability that ball drawn is even numbered ball. So even numbers are there which are even 1, 2, 3, 4, 5, even ball 5 by 11. How many prime numbers are there between 1 to 11? These are 2, 3, 5, 7 and 11 and these are 5 in numbers. So the probability of a ball having prime number 5 by 11. So the answer to the first part of the question is 6 by 11 to the second part answer is 5 by 11 and to the third part also answer is 5 by 11. So this completes the question and the session. Bye for now. Take care. Have a good day.