 Hi and welcome to our session. Let us discuss the following question. The question says, find the probability that the leap year selected at random will contain 53 Sundays. Let's now begin with the solution. We know that in a leap year, 366 days. Now 366 days means in a year we have 52 weeks and 2 days. The leap year which has 52 Sundays and the remaining 2 days can be Sunday and Monday, Monday and Tuesday, Tuesday and Wednesday, Wednesday and Thursday, Thursday and Friday, Saturday, Saturday and Sunday. With the sample space associated with this experiment, then total number of elementary events is equal to 7. Let A be the event that a leap year has Sundays. The leap year can have 53 Sundays only when the remaining 2 days are Sunday and Monday, Monday and Sunday. So these are the 2 favorable cases as event. So favorable number of elementary events are 2 and hence required probability is 2 by 7. As the number of favorable outcomes is 2 and total number of outcomes is 7. So required probability is 2 by 7. This is our required answer. So this completes the session. Bye and take care.