 Hello and welcome to the session. My name is Mansi and I'm going to help you with the following question. The question says find the equation of the circle with center 1 1 and radius root 2. So let us see the solution to this one. Now what is given to us is the center that is the point h k equal to 1 1 that is h is equal to 1 and k equals to 1 and the radius that is r equal to root 2. Now we know that equation of the circle with center h k and radius r is given by x minus h the whole square plus y minus k the whole square is equal to r square. Now we simply put in the values of h k and r in this equation and we get x minus 1 the whole square plus y minus 1 the whole square is equal to root 2 the whole square and this implies x square plus 1 minus 2x plus y square plus 1 minus 2y is equal to now square of root 2 is 2. This implies that x square plus y square minus 2x minus 2y equal to 0 because 1 plus 1 gives us 2. So this 2 in the left hand side gets cancelled with this 2 in the right hand side. So we say that our answer to this question is that equation of the circle with center 1 1 and radius root 2 is x square plus y square minus 2x minus 2y equal to 0. So I hope that you understood the question and enjoyed the session. Have a good day.