 Hi and welcome to our session. Let us discuss the following question. The question says, in each of the exercises 7 to 12, find the equation of the parabola that satisfies the given conditions. Coordinates of focus are 0 minus 3, the rectrix is y equals to 3. Before solving this question, we should know that if the parabola has vertex at the origin, focus at the point 0 minus a and the rectrix y equals to a, then equation of parabola is of the form x square equals to minus 4 a y. This is one of the standard equations of parabola. So keeping this in mind, let us now begin with the solution. We are given that coordinates of the focus are 0 minus 3 and the rectrix is y equals to 3. The focus 0 minus 3 lies on negative side of y axis. Now this implies that y axis is the axis of the parabola, parabola downwards like in this figure. 0 minus 3 in the form of 0 minus a, equation of rectrix y equals to 3 is in the form of y equals to a. We know that if the coordinates of focus are 0 minus a and equation of rectrix y equals to a, then equation of parabolas of the form x square equals to minus 4 a y. Now here, focus is also of the form 0 minus a and rectrix is of the form y equals to a. So this clearly implies that equation of parabola is of the form y equals to minus 4 a y. Now here a is equal to 3. So put in 3 in this equation in place of a, we get x square as minus 4 into 3 into y and this is equal to minus 12 y. So x square is equal to minus 12 y. So required equation of the parabola is x square equals to minus 12 y. So this completes the session. Bye and take care.