 Hello and welcome to the session. The given question says a circus tent is cylindrical to a height of 3 meters and conical above it if its base radius is 52.5 meters and slant height of the conical portion is 53 meters find the area of the converse required to make the tent So let's start with the solution and Suppose this is a circus tent, which is cylindrical to a height of 3 meters and then conical above it Here we are given that the height of the cylindrical portion is 3 meters and the base radius of this cone is 52.5 meters so this implies the radius of this cone is equal to the radius of this cylindrical portion Which is 52.5 meters so We are given that radius cylindrical portion is equal to the radius of conical portion and denoting it by small r is equal to 52.5 meters Also, we are given height of cylindrical portion denoting it by small h is equal to 3 meters and also we are given the slant height of the conical portion denoting it by small l and This is equal to 53 meters. We have to find the area of canvas required to make the tent therefore area of canvas required To make the tent is equal to the area of canvas required to make First the conical portion and then the area of canvas required to make the cylindrical portion So we need to find the curved surface area of this conical portion and then the curved surface area of cylindrical portion and then we shall add them Right so here we shall find the area of the circus tent and this is equal to the curved surface area of conical portion plus curved surface area of Cylindrical portion Now the curved surface area of conical portion is given by pi into r into l and the curved surface area of cylindrical portion is 2 pi r h Now taking pi and r common we have l plus 2 Edge now substituting the values Pi as we are given in the question is 22 by 7 Into the radius of the cylindrical and conical portion s 52.5 meters into L is 53 which is the slant height of the conical portion plus two times of 3 that is the height of the cylindrical portion So this is equal to 22 divided by 7 into 52.5 into 53 plus 6 which is equal to 22 divided by 7 into 52.5 into 59 Now 7 7's are 49 3 carry 0.75 so 35 so we have 22 into 7.5 Into 59 and on simplifying this we get 9735 and since all the quantities are in meters so here we have meters square Therefore our answer is area of Canvas required to make the tent is equal to 9735 meters square so this completes the session by intake care