 Hi and welcome to the session. I am Deepika here. Let's discuss the question. Question says, which of the given values of x and y make the following pair of matrices equal? A matrix of order 2 by 2 whose elements are 3x plus 7, 5, y plus 1, 2 minus 3x and another matrix is of order 2 by 2 whose elements are 0, y minus 2, 8, 4. Options are A, x is equal to minus 1 by 3, y is equal to 7, B not possible to find, C, y is equal to 7, x is equal to minus 2 by 3, D, x is equal to minus 1 by 3 and y is equal to minus 2 by 3. According to the definition of equal matrices, two matrices of the same order are equal if their corresponding elements are equal. This is the key idea behind this question. Let's start the solution. So, if given matrices are equal, that is, our given matrices are 3x plus 7 is one of the elements A, 1, 1, 5, y plus 1, 2 minus 3x. If it is equal to 0, y minus 2, 8 and 4, this will imply that 3x plus 7 must be equal to 0. Again, y minus 2 must be equal to 5 and y plus 1 must be equal to A and 2 minus 3, 2 minus 3x should be equal to 4. The relation gives x plus 7 is equal to 0 or x is equal to minus 7 by 3. Again, fourth relation gives 3x is equal to 4, which implies minus 3x is equal to 2, that is, x is equal to minus 2 by 3. From the first relation, we get x is equal to minus 7 by 3 and from the fourth relation, we get x is equal to minus 2 by 3. So, all the four relations does not hold for unique value of x. So, in other way, we can say there is no value of x for which both the vertex are equal. Hence, our answer is B not possible to find. I hope the question is clear to you. Bye and have a good day.