 Hi and welcome to the session. Let us discuss the following question. Question says find the values of the letters in the following and give reasons for the steps involved. Let us now move on to the solution. First of all we will rewrite the given puzzle. It is AB multiplied by 3 gives CAB. Now clearly you can see unit's digit of 3 multiplied by B is B. So we can write since one's digit of 3 multiplied by B is B it must be that B is equal to 0 or B is equal to 5. You know that when value of B is 0 then the product of 3 and 0 is 0 only or we can say unit's place of 3 multiplied by 0 is 0. And when value of B is 5 then unit's place of 3 multiplied by 5 is 5. So possible values of B are 0 or 5. Now here note that 3 multiplied by A is A. Now value of A cannot be 0 as A is the first digit of this number and we know that the first digit of a number cannot be 0. So value of A must be equal to 5. Now we can write one's digit of 3 multiplied by A is A only for A is equal to 5. This is because the first digit of a number cannot be 0. We know that 3 multiplied by A is equal to A is possible for only two values of A they are 0 and 5. Now since A cannot be equal to 0 so possible value of A is 5 and one's digit of 3 multiplied by 5 is 5 itself. Note that this value of A is correct only if the tenths place of 3 multiplied by B is 0. That is the product 3 multiplied by B does not produces any carry. Now clearly you can see tenths place of 3 multiplied by 0 is 0 for B is equal to 0. In case of B is equal to 5 tenths place is equal to 1 so value of B is 0. Now we can write A is equal to 5 is the correct value of A when tenths place of 3 multiplied by B is 0. So value of B is equal to 0. Now we can solve the puzzle as 50 multiplied by 3 gives 150. We get the value of A as 5 value of B is equal to 0 and value of C is equal to 1. So this is our required answer. This completes the session. Hope you understood the solution. Take care and bye for now.