 Let us start with the question that is given to us in this session. It says, find the general solution of the following equation. Now the eighth equation, general equation we need to find. The equation given to us is 6 squared 2x is equal to 1 minus tan 2x. First of all, let us start by factorizing the given equation to us. Now, as we started in our earlier crosses, according to one of the identities, 1 plus tan squared x can be written as 6 squared x. On using this identity, we can write this as 1 plus tan squared 2x is equal to 1 minus tan 2x. Right, proceeding on with the solution. Now here, these two will get cancelled out and we are left with tan squared 2x plus tan 2x is equal to 0. On taking out tan 2x common, we have tan 2x in bracket, we have tan 2x plus 1. Now, let us find out the general solution that can be tan 2x is equal to 0 or tan 2x plus 1 is equal to 0. And finding out we have 2x is equal to n pi that says x is equal to n pi by 2. And here, we have tan 2x is equal to minus 1 which is tan 2x is equal to minus 1 where minus 1 be written as tan 3 pi by 4. Right, and hence 2x is equal to 3 pi by 4 or x we can write it as 3 pi by 8. Therefore, the value of x comes out to be putting it into the general form. We have n pi by 2 plus 3 pi by 8 in where here also we had n pi with us. Right, so this becomes the second solution that we can have. So, these are the two alternative and hence this general solution is n pi by 2 or n pi by 2 plus 3 pi by 8 where n belongs to the set of integers. Right, so this is our quiet answer. I hope you enjoyed the session and do remember all your identities that you learned in your previous classes. Bye for now.