 Hello friends, so we are back with another theorem and this theorem says that if A, B and B, C are two Equal chords of the circle and the center of the circle Lies on the angular by angle by sector of the ABC angle ABC. Okay now We have drawn a circle And before that circle is actually passing through the given points. What are the given points? So we have drawn a B as three units and BC as three units and We have tried to you know bisect this angle ABC if you see So alpha is equal to beta. You can see the values over here 61.09 in this configuration and beta also 61.09 Okay, AB and length BC is given as three Okay, so and then what we did was we tried to draw The circle through ABC and we know the process. We have to basically draw up a nuclear bisectors of God's AB and BC and if you see they are intersecting at point Oh, which actually lies on the angle bisector here And if you think this could be because of one particular Configuration, so hence what we can do is we can change the positions of these three points So let's say you can see now as I'm changing the position of C The angles are varying but still the center is still on the angle bisector ABC. You can see that, right? So I keep on I'm changing the values or position of C, right? Similarly, I can change the position of B as well. So you can see that so as I change the position of B also in any which case The center is always lying on the perpendicular bisector. Now. We need to prove this We have validated through visualization like that. So yes, it does work, but why does it work? Let's see in the proof part