 Hello and welcome to the session. In this session we will discuss a question which says that solving the following system of equations using matrix method and the system of equations is given to us as pi h plus 2 times 2 y is equal to 0. Now before solving this solution of this question, we should know some results. Questions can be written in matrix form A x is equal to b where a is coefficient matrix, x is related matrix and b is constant matrix. And second is determinant of matrix A is not equal to 0, then inverse of matrix A i is this, that is matrix x is equal to inverse of matrix A into matrix B gets the solution. Now these results will work out as a key idea for solving out the given question. Now let us start with the solution of the given question to solve it using matrix method. Now from the key idea we know that a system of equations can be written in matrix form A x is equal to b and b is constant matrix in matrix form that is equal to b form. First of all let us write the coefficient matrix and this is equal to two of equations. Now in this system of equations the variables are given to us as x and y. First column we will write that the coefficients are of variable y that are two with elements in first row as 5 to and elements if it is right variable in column matrix. Now in this system of equations we have constant matrix b is also column matrix coefficient matrix A. So we have written the given system of equations in the form A x is equal to A is the coefficient matrix determinant of matrix A. Now this is the matrix A so determinant of matrix A determinant with elements in first row as 5 to and elements in second row is equal to this is equal to 10 that is equal to 4. Determinant of matrix A is equal to 4 which is not equal to 0. In any idea we know that if determinant of matrix A is not equal to 0 then the inverse of matrix A of the equation. Now here determinant of matrix A is not equal to 0 as d minus of matrix A into the matrix with elements in first row as d minus 1 upon determinant of matrix A into matrix with elements in first row as d minus d that is minus 3 of already found determinant of matrix A that is equal to 4 equal to 1 upon determinant is in second row as minus 3 by scalar 1 by inverse of matrix A is equal to so inverse of A is a matrix with elements in first row as 1 upon 2 minus 1 upon 2 and s minus 3 we have found inverse of now we know that into b gives the solution of the equation fix x and this is the matrix b so we have written all these matrices and these two matrices of matrices we have to check that number of columns in first matrix should be equal to number of rows in second dimension and dimension is plus 1 number of columns in first matrix is equals in second matrix these two matrices the resulting matrix would be of order to now multiplying the matrices we get of minus 1 by 2 into 0 will be minus 3 by 4 into 4 into 0 now further on solving that is a matrix having single matrix is equal to the column and now using equality of matrices and y is equal to minus 3 by solution have enjoyed the session