 Hi and welcome to our session. Let us discuss the following question the question sees. From a point on the ground at a distance x from the foot of a vertical wall, a wall is thrown at an angle of 45. It just clears the top of the wall and afterwards fights the ground at a distance of 5 on the other side of the wall. Find the height of the wall. Stand this by the diagram. This is the wall on the ground which is at a distance of x units from the foot of the initial velocity. z is u plus y that is horizontal range is equal to u square t divided by g. The equation of projectile motion is given by equals to x tan alpha minus 1 by 2 into g x square divided by u square cos square 45 and u square is equal to x plus y into...