 Hello and welcome to the session. In this session we discussed the following question which says, construct a triangle PQR in which QR is equal to 5 centimeters, PQ is equal to 3 centimeters, and RP is equal to 3.5 centimeters. Draw the perpendicular bisector of the side QR. Let's move on to the solution now. First we'll draw the rough sketch of the triangle PQR. This is the triangle PQR in which we are given QR is of length 5 centimeters, PQ is of length 3 centimeters, and PR or RP is of length 3.5 centimeters. Now we'll do this construction step by step. So first of all we have, draw a line segment QR equal to 5 centimeters. So this line segment QR is of measure 5 centimeters. Now from the rough figure as you can see that PQ is of measure 3 centimeters. So in the next step we have with Q as the center and radius 3 centimeters, draw an arc. So taking Q as the center and radius as 3 centimeters we have drawn this arc. Then as you can see in the triangle that is in the rough sketch of triangle PQR, PR is of measure 3.5 centimeters. So in the third step we have with R as the center and radius equal to 3.5 centimeters, draw an arc, cutting the previous arc. At this point of intersection of the two arcs be the point P, then join PQ and PR. So we have joined PQ and PR, so triangle PQR is the required triangle in which QR is of measure 5 centimeters, PQ is of measure 3 centimeters and PR is of measure 3.5 centimeters. Also we are supposed to draw the perpendicular bisector of the side QR. So our next step would be with Q as center and radius equal to more than half of QR draw arcs on both sides of QR. So we have drawn these two arcs taking Q as the center and radius more than half of QR. Now in the next step we have with R as the center and radius equal to more than half of QR draw arcs on both sides of QR, cutting the previous arcs A and B. So we have drawn these two arcs, let this point of intersection of the two arcs be point A and this point of intersection of the two arcs be point B. Now we join AB, so we have joined AB, so this AB is the perpendicular bisector of the side QR of triangle PQR. So this completes the session, hope you have understood the solution for this question.