 Hello and welcome to the session. In this session we discussed the following question which says, construct a parallelogram ABCD in which AB is equal to 3.5 cm, BC is equal to 3 cm and height is equal to 2.5 cm. So we have to construct a parallelogram ABCD in which we are giving two adjacent sides and height. So let's start with the construction now. First of all let us draw a rough figure for the parallelogram ABCD which is to be constructed. This is the parallelogram ABCD in which we have AB equal to 3.5 cm, BC equal to 3 cm and the height that is say BE is equal to 2.5 cm. Now we will start the construction step wise for which we would follow some steps of construction. A first step of construction would be draw a straight line AB equal to 3.5 cm. This is the straight line AB of measure 3.5 cm. Now as we know that in a parallelogram opposite sides are parallel so this AB would be parallel to CD and CD is at a perpendicular distance of 2.5 cm from AB. In the next step we would draw XY parallel to AB at a perpendicular distance of 2.5 cm. We have drawn this perpendicular BQ at B. Now we need to draw a line parallel to AB which is at a distance of 2.5 cm from AB. So on this perpendicular with B as the centre and radius 2.5 cm we will draw an arc. So we have drawn this arc on the perpendicular BQ. Let this point of intersection of the arc and the perpendicular BQ be the point E. Since we have BE is equal to 2.5 cm. Now to draw XY parallel to AB we would draw a straight line through the point E. So we have drawn this line XY which is parallel to AB and is at a distance of 2.5 cm from AB. That is we have BE equal to 2.5 cm. Now since we know that in a parallelogram opposite sides are equal also. So this means if AB is equal to 3.5 cm so CD would also be equal to 3.5 cm. If BC is 3 cm then AB would be 3 cm. Now we need to locate the points C and D of the parallelogram AB-CD. The next step we have with A as centre and radius equal to 3 cm draw an arc to cut XY at the point D. We have drawn this arc with A as the centre and radius equal to 3.5 cm such that this arc cuts the line XY at the point D. So this is the point D. Now in the next step we have with B as centre and radius equal to 3 cm draw an arc to cut XY at point C. So we have drawn this arc with B as the centre and radius equal to 3 cm such that this arc cuts the straight line XY at the point C. Then finally we join AD and BC. So on joining AD and BC we get the required parallelogram AB-CD in which we have AB equal to 3.5 cm, BC equal to 3 cm, AD equal to 3 cm and the distance between the two parallel lines or you can say the height of the parallelogram that is BE as 2.5 cm. Thus we have AB-CD is the required parallelogram. This completes the session. Hope you have understood the solution of this question.