 Welcome to your session. Let us discuss the following question. The question says evaluate integral of 1 by the square root of x plus 3 minus square root of x plus 2 with respect to x. Let i is equal to integral of 1 by square root of x plus 3 minus square root of x plus 2 with respect to x. However, multiply and mutate the denominator by root of x plus 3 minus root of x plus 2. So this is equal to 1 by root x plus 3 minus root x plus 2 into root x root x plus 2 divided by root x plus 3 plus root x plus 2 dx. This is equal to integral of root x plus 3 plus 2 divided by root x plus 3 whole square root x plus 2 whole square equal to integral of with respect to integral of square root of x plus 2 with respect to x. We know that integral of to the power 8 with respect to x1 divided by n plus 1 into a plus c with respect to x. This is equal to x plus 3 to the power 1 by 2 plus 1 divided by 1 by 2 plus 1 plus x plus 2 to the power 1 by 2 plus 1 divided by 1 plus 2 plus 1 plus 3. This is equal to 2 by 3 into x plus 3 to the power 3 by 2 plus 2 by 3 into x plus 2 to the power 3 by 2 plus 2 by 3 into x plus 2 to the power 3 by 2 plus c. This is our required answer. So this completes the session. Bye and take care.