 Hello all and welcome to the session. Today the question is, construct a triangle ABC in which BC is equal to 5 cm, angle B is equal to 45 degrees and angle C is equal to 60 degrees. Draw the circle of the triangle ABC. And now we will start with the solution. Now first of all we will draw a rough figure that is a rough diagram of a triangle ABC where angle B is equal to 45 degrees and angle C is equal to 60 degrees and BC is equal to 5 cm. Now we will start with the steps of construction. First of all we will draw a line segment BC is equal to 5 cm. Now here you can see we have drawn a line segment BC which is 5 cm. And now in the second step we will construct an angle CBX is equal to 45 degrees. As you can see here we have constructed an angle CBX is equal to 45 degrees. And now in the third step we will construct an angle BCY is equal to 60 degrees. As you can see here we have constructed an angle BCY which is equal to 60 degrees. Now let the A, BX and CY intersect at A. BX and CY let this point be A and hence ABC is the required triangle. Now in the fourth step draw BQ and RS perpendicular bisectors of CY, A, B and BC respectively leading each other at all. Now you can see here BQ is the perpendicular bisector of the CY AB and RS is the perpendicular bisector of CY BC and both of them are intersecting at point O. Now in the last step with all of the CY and OA as radius draw a circle such that it passes through the points A, B and C. Now you can see here with all as the center and OA as the radius we have drawn the circle which is passing through the point A, B and C and this is called the circle circle of the triangle ABC. So this is the required construction and that's all for this session. Hope you all have enjoyed the session.