 Hi. Welcome to the session. I am Deepika here. Let's discuss the question. Find the values of k for the quantity equation so that they have two equal rules. 2x square plus kx plus 3 is equal to 0. Let's start the solution. Solution. Our given equation is 2x square plus kx plus 3 is equal to 0. On comparing with ax square plus bx plus c is equal to 0, we get a is equal to 2, b is equal to k and c is equal to 3. Let us first find out the discriminant that is b square minus 4ac. This is equal to k square minus 4 into 2 into 3 which is equal to k square minus 24. Now we know that for equal rules we have discriminant should be equal to 0. So for equal rules k square minus 24 should be equal to 0. This implies k square is equal to 24 which implies k is equal to plus minus root 24. Again this is equal to k is equal to plus minus 2 root 6. Hence for k is equal to plus minus 2 root 6, the given quadratic equation has equal rules. Therefore k is equal to plus minus 2 root 6 is your answer. Hope the question is clear to you. Bye and have a nice day.