 If the acceleration is constant, a straight line motion, what it will be constant at V2? So V2 minus V1 is constant, the velocity time graph will be a straight line. I am going sequentially step by step. So the basics, they will realize that the most difficult problem also, they will be able to solve it. Because you are not able to think, that will not help you. Any doubts? Till now? Okay, now I want you to draw, suppose it is moving a straight line, it is constant. Can you plot xt graph? Okay, somebody said this. Over here, is it close to zero or not? xt is not changing there. If the time changes little bit, xt remains more or less same. So I can say that xt is not changing. Over here, this much change is there. Same on this much. Are you getting it? It is increasing. Velocity is decreasing. Velocity is decreasing. Can you plot it and then speed? Velocity is decreasing. See the way myself again, the understanding becomes better and better. The gradient decreases. Others? Then? Okay, not that. What about this? What is happening here? It is going backward. xt is going backward. Is it xt? Is it xt? What is that? This much distance, same amount of time. Getting it to ten, now it is coming to xt below zero. Moving backward. And now it is this direction. And then it will push this way forward. Sorry, backwards. Let us take more. Why more? Okay guys, it becomes straight line. What? Velocity? It moves towards the xt axis but it does not catch it. There will be some xt. It is standing to zero. See this relationship decreases the magnitude. But xt is in initial backwards. Okay, acceleration. But when it is going backwards and studied separately. Okay.