 Hello friends, welcome to the session. I am Malka and today we are going to find the roots of quadratic equation given in question first above by applying the quadratic formula. Our given equation is 2x square plus x minus 4 equal to 0. Now, let's start with the solution. Our given equation is 2x square plus x minus 4 equal to 0. Now, we will compare this equation with ax square plus vx plus c equal to 0. Then we have a equal to 2b equal to 1 and c equal to minus 4. Now, we can calculate the value of d which is d equal to v square minus 4ac. Therefore, this gives 1 square minus 4 into 2 into minus 4. This gives us 1 square plus 32. This implies d equal to 33. Now, we can calculate the roots alpha and beta. Now, alpha equal to minus b plus square root of d upon 2a and beta equal to minus b minus square root of d upon 2a. Here, alpha equal to minus 1 plus square root of 33 upon 2 into 2 and beta equal to minus 1 minus square root of 33 upon 2 into 2. This implies alpha equal to minus 1 plus square root of 33 upon 4 and beta equal to minus 1 minus square root of 33 upon 4. Hence, the roots are minus 1 plus square root of 33 by 4 and minus 1 minus square root of 33 by 4 which is the required solution. Hope you understood it and enjoyed the session. Goodbye and take care.