 Next question, minus 2, 0, 2, multiple options can be correct, correct 2 seconds using the graph. This is 4, sorry about that, this is 4. How much distance will be travelled before the correction? Could be correct, one of the options is correct. I'll tell you later, first solve A and C also. See, I mean R B is very straight forward. Acceleration is strong strength, so U plus 80. Simple, U is 0, A is 4, A is 2, where? This is the position vector, I will integrate it from 0 to T. This is equal to P square plus, so final position vector is 4 by 10, U plus 3 J dot. Understood test, all of you understood, 1 DT plus 3 DT. So, DT will come inside, 2DT integral is 2T square by 2, so I'll skip a couple of steps. So, this is a Y minus 3 by 3, substitute this value of T, one of those routine questions. Which you might be doing it for first time, but that if I give the same question in a