 Hello and welcome to the session. In this session we are going to discuss the following question and the question says that Tabatha inspects the bulge coming from a factory. From initial observations she expects 1 out of 7 bulge to be defective. What objects can be used for simulation to know possible outcomes of the inspection? Perform the simulation and find the experimental probability. We know that probability of an event is given by favorable outcomes upon total number of outcomes. With this key idea let us proceed to the solution. In this question Tabatha has to find the probability of the number of defective bulge from the lot. She expects 1 out of 7 bulge to be defective. So according to Tabatha 1 out of 7 bulge are defective. Therefore expected probability to find the number of defective bulge will be given by favorable outcomes upon total number of outcomes and here favorable outcomes is given by 1 and the total number of outcomes are 7. So probability would be equal to 1 by 7 that is 0.142 or we can write it in the percentage form as 15.2%. And here in this question we need to find what objects can be used for simulation to know possible outcomes of the inspection and we need to perform the simulation and find the experimental probability. So here we should know that simulation is an imitation of a real object or simulation so here we use a simulation having 7 objects where 1 out of 7 objects represents a defect. We place 7 models in a bar with 6 models R of white color and 1 model is with red color. Here red colored model represents defective bulge. Without looking at it take out one model and note down the result and replace the model in the jar. Now repeat this process 6 more times representing the bulge. The draw of 7 models 1 simulation and thus 1 simulation has 7 trials. Suppose we perform 2 such simulations which means we will have 60 into 7 trials which is equal to 420 trials and we get the following reading that is W denoting the white model W, W, R which denotes the red model W, W, R, W, W, W and so on. And let us suppose out of 420 trials 65 times where model W den, experimental probability written as defective bulge will be given by 65 upon 420 using the same formula that is favorable outcomes upon total outcomes. And this is equal to 0.154 or can be written in percentage form as 15.4%. So we can say experimental probability of getting defective bulge is given by 0.154 or 15.4% which is the required answer. This completes our session. Hope you enjoyed this session.